Find the common difference of this A.P.

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Homework Help Overview

The problem involves distinct positive real numbers a, b, and c in geometric progression (G.P.), with the logarithmic expressions log_c a, log_b c, and log_a b being in arithmetic progression (A.P.). The objective is to find the common difference of this A.P.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss substituting variables for clarity and ease of manipulation. There are attempts to express the logarithmic relationships in terms of A, B, and C. Some participants question the meaning of A.P. and G.P., expressing confusion over the acronyms used.

Discussion Status

The discussion is ongoing, with some participants providing guidance on variable substitution and expressing concerns about clarity in communication. There is no explicit consensus on the interpretation of the acronyms or the approach to the problem.

Contextual Notes

There are mentions of potential ambiguity in the use of acronyms, with participants noting the importance of clear definitions in mathematical discussions. Some participants have expressed frustration over the lack of clarity in the original post.

utkarshakash
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Homework Statement


If a,b,c are distinct positive real numbers in G.P. and log_c a,log_b c,log_a b are in A.P., then find the common difference of this A.P.

Homework Equations



The Attempt at a Solution


b^2=ac \\<br /> 2log b=log a+log c
Also
2\dfrac{log c}{log b}=\dfrac{log a}{log c}+\dfrac{log b}{log a}
 
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I suggest substituting A = log a etc, just to make it easier to read/write.
Since you are asked for the common difference, it might help to invent a variable for that and use it to substitute for some of A, B, C.
 
utkarshakash said:

Homework Statement


If a,b,c are distinct positive real numbers in G.P. and log_c a,log_b c,log_a b are in A.P., then find the common difference of this A.P.

Homework Equations



The Attempt at a Solution


b^2=ac \\<br /> 2log b=log a+log c
Also
2\dfrac{log c}{log b}=\dfrac{log a}{log c}+\dfrac{log b}{log a}

Does A.P. mean "Associate Press", "Audio Precision", "Advanced Placement", or what? These are what I get (among many others) when I do Google. To me, G.P. stands for "Geometric Programming", which is a branch of Optimization used widely in engineering and similar fields. Oh... maybe you mean "arithmetric progression" and "geometric progession", but I cannot say for sure, not being a mind-reader.

RGV
 
Ray Vickson said:
Does A.P. mean "Associate Press", "Audio Precision", "Advanced Placement", or what? These are what I get (among many others) when I do Google. To me, G.P. stands for "Geometric Programming", which is a branch of Optimization used widely in engineering and similar fields. Oh... maybe you mean "arithmetric progression" and "geometric progession", but I cannot say for sure, not being a mind-reader.

RGV

If you do know some maths then you MIGHT NOT ask these useless questions. Is common difference related to "Associate Press", "Audio Precision", "Advanced Placement" in any way?
 
utkarshakash said:
If you do know some maths then you MIGHT NOT ask these useless questions. Is common difference related to "Associate Press", "Audio Precision", "Advanced Placement" in any way?[/QUOTE

No, they are not useless questions---they are supposed to make you realize that using undefined acronyms is not a good policy. Effective communication is an important part of problem-solving. I am not the only poster who has had problems with your presentations. What, exactly, is so hard about writing out "arithmetic progression" or "geometric progression" (or, for that matter, "harmonic progression")? If you wanted to save space you could say 'arithmetic progression (AP)', then use 'AP' after that in the same posting/thread (but not in different threads).

BTW: I do know some maths, having had honours undergrad work in the subject and a few graduate courses in it at MIT, as well as having taught math-related subjects (Operations Research) at university for more than 30 years. So, that little criticism of yours does not wash.

RGV
 
utkarshakash said:
If you do know some maths then you MIGHT NOT ask these useless questions. Is common difference related to "Associate Press", "Audio Precision", "Advanced Placement" in any way?
utkarshakash, mind your manners! We're trying to help you and many like you. There are many branches of mathematics. Abbreviations like that are fine once you're tuned into the branch in question, but you must understand that we come into each post cold. On one of your posts today I read, up front, that such and such were in G.P. My first thought was "general position". We're not mind readers. It is up to you to try to make things clear so that we can get the picture easily.
 
haruspex said:
utkarshakash, mind your manners! We're trying to help you and many like you. There are many branches of mathematics. Abbreviations like that are fine once you're tuned into the branch in question, but you must understand that we come into each post cold. On one of your posts today I read, up front, that such and such were in G.P. My first thought was "general position". We're not mind readers. It is up to you to try to make things clear so that we can get the picture easily.

OK I won't post questions involving such ambiguity in future.
 
haruspex said:
I suggest substituting A = log a etc, just to make it easier to read/write.
Since you are asked for the common difference, it might help to invent a variable for that and use it to substitute for some of A, B, C.

OK as you said I assumed A as log a and so on.

\dfrac{A}{C},\dfrac{C}{B},\dfrac{B}{A} are in Arithmetic Progression.

Also the common difference of this Arithmetic Progression is given by
\dfrac{\frac{B}{A}-\frac{A}{C}}{3-1}

To find the value of the numerator I substitute B=(A+C)/2;

After simplifying I get

\dfrac{1-\frac{C}{A}-\frac{A}{C}}{2}
 
utkarshakash said:
OK as you said I assumed A as log a and so on.

\dfrac{A}{C},\dfrac{C}{B},\dfrac{B}{A} are in Arithmetic Progression.

Also the common difference of this Arithmetic Progression is given by
\dfrac{\frac{B}{A}-\frac{A}{C}}{3-1}

To find the value of the numerator I substitute B=(A+C)/2;

After simplifying I get

\dfrac{1-\frac{C}{A}-\frac{A}{C}}{2}
What I meant was, let x = C/B, A/C = x-y, B/A = x+y. You should get down to specific values (perhaps several choices) for x and y.
 

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