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Find the curvature at a point(vector function)

  1. Oct 23, 2011 #1
    1. The problem statement, all variables and given/known data
    Find the curvature of r(t)= <t^2, lnt, t lnt> at the point P(1,0,0)


    2. Relevant equations
    K(t) = |r'(t) x r''(t)|/(|r'(t)|^3)


    3. The attempt at a solution
    r'(t) = <2t, t^-1, lnt+1>
    r''(t) = <2, -t^-2, t^-1>

    |r'(t) x r''(t)| = sqrt[t^-4(4 + 4 lnt + ln^2t) + (4 ln^2t)]
    |r'(t)| = sqrt[4t^2 + t^-2 + (ln^2t +2 lnt + 1)]

    I don't know what value of (t) to sub into K(t) to get my final answer. I also have a feeling that my cross product is not right. Any help would be much appreciated.
     
  2. jcsd
  3. Oct 23, 2011 #2

    HallsofIvy

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    You want [itex](t^2, ln(t), tln(t))= (1, 0, 0)[/itex].

    What value of t gives you that?

    You are right that your cross product is wrong. Put your value of t into r' and r'' before calculating the cross product. That will simplify it a lot.
     
  4. Oct 23, 2011 #3
    Thanks a lot HallsofIvy, t = 1 provided I did the rest of the question right.
     
  5. Oct 23, 2011 #4

    HallsofIvy

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    t= 1 whether you did the rest of the problem right or not!
     
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