Find the derivative of the vector function

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To find the derivative of the vector function r(t) = ta x (b + tc), it is essential to recognize that t is the only variable, while a, b, and c are constant vectors. The expression can be simplified to r(t) = (a x b)t + (a x c)t^2. When differentiating with respect to t, apply the product rule, treating the constants appropriately. The derivative will involve the cross products of the vectors and their respective coefficients. Understanding that the constants remain unchanged during differentiation is crucial for solving the problem.
xstetsonx
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Find the derivative of the vector function r(t) = ta x (b + tc)
a=<-2,2,-1> b=<-1,1,1> c=<-2,2,4>


I know r(t)=ta x (b + tc)=(axb)t+(axc)t^2
then i got lost
 
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Hi xstetsonx! :smile:

(try using the X2 tag just above the Reply box :wink:)
xstetsonx said:
I know r(t)=ta x (b + tc)=(axb)t+(axc)t^2

ok, now differentiate wrt t. :smile:
 
don't know how because they are all numbers. Should i do the cross product or what do i do?
 
uhh? everything except t is a constant :confused:
 
Everything except t is a constant vector. t is the only numeric variable in the problem.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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