Find the displacement of the springs

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A question:Simple harmonic motion

http://capa2.cc.huji.ac.il/res/msu/physicslib/msuphysicslib/09_Force_and_Motion/graphics/prob07_twospring.gif1.[/URL] Homework Statement
Two springs with spring constants k1=29.7 N/m and k2=20.7 N/m are connected as shown in the figure:
Find the displacement, y, of the connection point from its initial equilibrium position when the two springs are stretched a distance d = 1.10 m as a result of the application of the force F

http://capa2.cc.huji.ac.il/res/msu/physicslib/msuphysicslib/09_Force_and_Motion/graphics/prob07_twospring


Homework Equations


Hooks law: F=Kx



The Attempt at a Solution


since the same the same force streches each spring :
k1.x=k2.x
FROM HERE I STUCKED
ANY HINT?
 
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i tried to figure this question out:
F=(l1+1.10)29.7
F=(l1+y+1.10)20.7
y=9
but its not correct
any help?
 
Two springs with spring constants k1=29.7 N/m and k2=20.7 N/m are connected as shown in the figure:
What figure?
 
http://capa2.cc.huji.ac.il/res/msu/physicslib/msuphysicslib/09_Force_and_Motion/graphics/prob07_twospring.gif
 
Last edited by a moderator: