Find the equation of tangent line

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SUMMARY

The discussion focuses on finding the equation of the tangent line for the parametric equations x=2sin(t) and y=tan(t) at t=0. To determine the tangent line, participants emphasize the necessity of calculating the gradient using the chain rule, specifically dy/dx = (dy/dt)/(dx/dt). Additionally, identifying the point on the curve at t=0 is crucial for constructing the tangent line equation.

PREREQUISITES
  • Understanding of parametric equations
  • Knowledge of differentiation and the chain rule
  • Ability to compute dy/dx for parametric functions
  • Familiarity with the concept of tangent lines in calculus
NEXT STEPS
  • Practice finding tangent lines for various parametric equations
  • Learn how to apply the chain rule in differentiation
  • Explore the implications of parametric equations in real-world scenarios
  • Study the behavior of trigonometric functions in calculus
USEFUL FOR

Students studying calculus, particularly those focusing on parametric equations and tangent line concepts, as well as educators seeking to enhance their teaching methods in these areas.

th3plan
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Homework Statement



Find equation of the tangent line at t=0

x=2sint
y=tant




The Attempt at a Solution



Really don't know where to start, can someone give me the hint, don't solve it, i want to try it, just need a hint
 
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To find the equation of any line,you need a point on the line and the gradient on the line.

To find the gradient at t=0,you'll need to find dy/dx (chain rule is helpful here)

and you'll need a point on the line, you want at t=0 ,so can you find the point on the line,(x,y) when t=0?
 
dy/dx=(dy/dt)/(dx/dt). Then go with rock.freak667's advice.
 

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