Find the equation of the line tangent to the graph

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Homework Help Overview

The discussion revolves around finding the equation of the tangent line to the graph of the function y=x^2 at the specific point (1/2, 1/4). Participants are exploring the concepts of derivatives and tangent lines in the context of calculus.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using the derivative to determine the slope of the tangent line and question the process of finding the equation with a given slope and point. There are attempts to clarify the correct form of the tangent line equation.

Discussion Status

Some participants have provided guidance on using the derivative to find the slope and have noted the importance of showing effort in solving the problem. There are differing interpretations of the tangent line equation, and participants are actively engaging with each other's reasoning.

Contextual Notes

One participant mentions a potential misunderstanding in the equation they wrote, indicating a need for clarity in the setup and calculations. There is an emphasis on the requirement to demonstrate effort before receiving assistance.

sashashow
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Find the equation of the line tangent to the graph of y=x^2 at the point (1/2,1/4)


and how to find that?
 
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Use the derivative of y=x^2 to find the slope. If you have a slope and a point, can't you find the equation? Isn't it in your textbook someplace? You have to show an effort to solve the problem before anyone can help you.
 
i found the y'=2x so m=1. But I wrote the wrong equation which is y=x+1/4.
 
The equation is (y-1/4)=1*(x-1/2) isn't it? As in (y-y0)=m*(x-x0) where m is the slope and (x0,y0) is the point??
 

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