Find the equation of the line tangent to the graph

sashashow
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Find the equation of the line tangent to the graph of y=x^2 at the point (1/2,1/4)


and how to find that?
 
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Use the derivative of y=x^2 to find the slope. If you have a slope and a point, can't you find the equation? Isn't it in your textbook someplace? You have to show an effort to solve the problem before anyone can help you.
 
i found the y'=2x so m=1. But I wrote the wrong equation which is y=x+1/4.
 
The equation is (y-1/4)=1*(x-1/2) isn't it? As in (y-y0)=m*(x-x0) where m is the slope and (x0,y0) is the point??
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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