Find the equation of the plane parallel to two lines

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SUMMARY

The discussion focuses on finding the equation of a plane in a three-dimensional vector space (V3) that contains two lines through point A, parallel to vectors B and C, which are distinct and non-parallel. The equation of the plane is derived using the cross product of vectors B and C, expressed as \(\left( \left< x,\quad y,\quad z \right> -\overrightarrow { OA } \right) \cdot \overrightarrow { B } \times \overrightarrow { C } =0\). Participants clarify the terminology, confirming that V3 is equivalent to \(\mathbb{R}^3\), and discuss the verification of the lines lying within the plane.

PREREQUISITES
  • Understanding of vector operations in three-dimensional space
  • Familiarity with the concept of cross products
  • Knowledge of vector equations of planes
  • Basic comprehension of linear algebra and vector spaces
NEXT STEPS
  • Study the properties of cross products in vector mathematics
  • Learn how to derive equations of planes from vector equations
  • Explore the geometric interpretation of lines and planes in \(\mathbb{R}^3\)
  • Investigate the implications of distinct and non-parallel vectors in vector spaces
USEFUL FOR

Students studying linear algebra, mathematicians focusing on vector spaces, and anyone interested in geometric interpretations of vector equations.

Sho Kano
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Homework Statement


Let A, B and C be distinct vectors in V3 with B and C non-parallel.
a. Find an equation for the plane containing both the line through A parallel to B and the line through A parallel to C.
b. Verify that the two lines actually lie in the plane.

Homework Equations

The Attempt at a Solution


I can't see any situation where a plane containing A can be parallel to a plane containing C if they are distinct vectors (distinct as in non-parallel)
 
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Sho Kano said:

Homework Statement


Let A, B and C be distinct vectors in V3 with B and C non-parallel.
What is V3? Presumably it's a 3-dimensional vector space. If so, is it different from ##\mathbb{R}^3##?
Sho Kano said:
a. Find an equation for the plane containing both the line through A parallel to B and the line through A parallel to C.
This is a very strange description. The context here seems to be that A is a point, but the earlier description is that A is a vector. I would guess that what they're calling vector A is the vector ##\vec{OA}##, with O being the origin and A being the endpoint of the vector. Otherwise this problem doesn't make much sense.

Was the problem statement originally in some other language?
Sho Kano said:
b. Verify that the two lines actually lie in the plane.

Homework Equations

The Attempt at a Solution


I can't see any situation where a plane containing A can be parallel to a plane containing C if they are distinct vectors (distinct as in non-parallel)
 
The question is not well expressed. Here is what I think they mean.

Let A,B,C be three points in ##\mathbb R^3## and denote the origin by ##O##.

Let L1 be a line through A that is parallel to line segment ##\bar{OB}##.
Let L2 be a line through A that is parallel to line segment ##\bar{OC}##.

(b) Show that there is a plane that contains both L1 and L2; and
(a) find the equation of that plane.
 
Sho Kano said:

Homework Statement


Let A, B and C be distinct vectors in V3 with B and C non-parallel.
a. Find an equation for the plane containing both the line through A parallel to B and the line through A parallel to C.
b. Verify that the two lines actually lie in the plane.

Homework Equations

The Attempt at a Solution


I can't see any situation where a plane containing A can be parallel to a plane containing C if they are distinct vectors (distinct as in non-parallel)

While the question is not absolutely clear, I think one interpretation of it is that we have two vectors ##\vec{B}## and ##\vec{C}## in a 3-dimensional space; these are, perhaps, like force vectors or velocity vectors, having tails and heads not necessarily at the origin. Assuming that is the case, make a copy ##\vec{C}'## of ##\vec{C}## but whose tail coincides with the tail of ##\vec{B}##, so that ##\vec{B}## and ##\vec{C}'## emanate from the same point in space, but have different directions. There certainly IS a plane P that contains both vectors ##\vec{B}## and ##\vec{C}'## (that is, which contains the three points that lie at the two ends of these vectors). Any Plane P that is parallel to P will be parallel to both vectors ##\vec{B}## and ##\vec{C}## (the original ##\vec{C}##), and now all you need to is figure out which such plane passes through the point A which lies at the end of the vector ##\vec{A}## (assuming that this last vector has its tail at the origin).
 
Mark44 said:
Was the problem statement originally in some other language?
I copied the problem straight off the problem set; I'll try to clarify with the teacher today
 
Mark44 said:
What is V3? Presumably it's a 3-dimensional vector space. If so, is it different from R3R3\mathbb{R}^3?
There's no difference, my teacher just likes to use V3 as a distinction from R3 (for whatever reason) for the first few days of the class
 
OK so apparently, we are supposed to find a plane that has both B and C in it, and A intersecting it. It makes sense because a plane can be parallel to many vectors.
The equation of such a plane can be \left( \left&lt; x,\quad y,\quad z \right&gt; -\overrightarrow { OA } \right) \cdot \overrightarrow { B } \times \overrightarrow { C } =0 right?
Then I guess I just do part b by plugging in OA + tB and OA + tC.
 
Last edited:

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