Find the equation of the tangent line to the curve 3xy = x^3 + y^3 at point (2/3,4/3)
The Attempt at a Solution
I found the deriviative to be 3x^2-3y / 3x - 3y^2 which i simplified to x^2 - y / x - y^2
I found the slope of at those points to be - 1/2
Then using the y - y1 = m(x - x1) formula I got 3x + 3y - 10 = 0 for the equation.
What do you guys think?