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## Homework Statement

Find the equation of the tangent line to the curve 3xy = x^3 + y^3 at point (2/3,4/3)

## Homework Equations

## The Attempt at a Solution

I found the deriviative to be 3x^2-3y / 3x - 3y^2 which i simplified to x^2 - y / x - y^2

I found the slope of at those points to be - 1/2

Then using the y - y1 = m(x - x1) formula I got 3x + 3y - 10 = 0 for the equation.

What do you guys think?