Find the equations for the two tangent lines.

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SUMMARY

The discussion focuses on finding the equations for two tangent lines to the graph of the function f(x) = - (x-3)^2 - 4 that pass through the point (2,5). The derivative f '(x) was calculated as -2x + 6, yielding a slope of 2 when evaluated at x = 2. However, it was established that the point (2,5) does not lie on the curve, indicating that the tangent line at x = 2 does not intersect (2,5). To find the second tangent line, one must derive the slopes from points on the curve that connect to (2,5) and ensure they match the derivative.

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Homework Statement


Find the equations for the two tangent line on the graph f(x) = - (x-3)^2 - 4 through the point (2,5)

Homework Equations


The Attempt at a Solution


I already solved for f '(x) which is -2x +6. Then I plug in 2 for f '(x) in order to find the slope, which is 2. Using the equation y - y1 = m(x -x1) I found the equation for my first tangent line to be y = 2x+1. My question is how do i find the second tangent line, and did I do something wrong?
 
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The point (2,5) is not on the curve y = f(x). Furthermore, the tangent line to f(x) at x=2 does not pass through the point (2,5). y=f(x) is a parabola, you need to consider the lines from points (x,f(x)) on the curve that pass through (2,5) and then solve for the lines whose slope matches f'(x).
 

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