Find the equivalent resistance of a circuit below

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SUMMARY

The equivalent resistance of a circuit consisting of six 12-ohm resistors was calculated incorrectly in the forum discussion. The correct approach involves combining resistors R5 and R6 in parallel to form R56, followed by a series connection with R4, and continuing through the circuit until reaching R1. The final equivalent resistance (Req) is determined to be 20Ω, but the calculations require careful attention to the parallel and series combinations of resistors, specifically using the formula for parallel resistors: 1/R_total = 1/R1 + 1/R2.

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shashaeee
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Find the equivalent resistance of the circuit shown below. Each of the six resistors has a resistance of 12 ohm.
physics.jpg


I just want to make sure I calculated everything right. I don't have the solution available.

Labelling the resistors from my left to the right: R1, R2, R3, R4, R5(bottom), R6

What I did:

R5 + R6 = R56

1/R56 + 1/R4 = R456

R456 + R3 = R3456

1/R3456 + 1/R2 = R23456

R23456 + R1 = Req = 20Ω

Thanks!
 
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Your logic all looks correct to me. I don't have a calculator available, but your work looks fine and the answer seems reasonable.

Edit: The post below me is correct, I missed those errors.
 
Last edited:
shashaeee said:
1/R56 + 1/R4 = R456

No, 1/R56 + 1/R4 = 1/R456


1/R3456 + 1/R2 = R23456

No, 1/R3456 + 1/R2 = 1/R23456
 
The resistors are of equal value.
In calculation this value is substituted in the equations.
R5+R6=2R
Next the parallel resistor
2R.R/(2R+R)=2R/3
And the next configuration till R1
 
Thanks guys!
 

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