Find the expectation value of momentum squared for a simple harmonic oscillator

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Homework Help Overview

The discussion revolves around finding the expectation value of momentum squared for a simple harmonic oscillator, specifically using the ground state wave function ψ0(x) = A0e−ax2. Participants are exploring the mathematical implications of the momentum operator and its application in quantum mechanics.

Discussion Character

  • Mathematical reasoning, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to compute the expectation value using the given wave function and the momentum operator, expressing concern over the negative result obtained. Some participants suggest using the Virial Theorem or an algebraic approach, while others question the necessity of taking derivatives and suggest using creation and annihilation operators instead.

Discussion Status

Participants are actively engaging with the problem, with some offering alternative methods and questioning the steps taken by the original poster. There is recognition of potential missing factors in the calculations, and the discussion is exploring various interpretations of the problem without reaching a consensus.

Contextual Notes

There is mention of specific constants and expressions, such as the value of 'a' and the normalization constant A0, which may influence the calculations. The complexity of the integrals involved is acknowledged, and participants are considering different approaches to simplify the process.

goolsby
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Find the expectation value of (px)2, keeping in mind that ψ0(x) = A0e−ax2
where A0 = (2mω0/h)^1/4, and
<x2> = ∫x2|ψ|2dx = h_bar / 2mω0


<ψ(x)|px2|ψ(x)> = ∫ψ(x)(pop2)ψ(x) dx

pop = [hbar / i] ([itex]\delta[/itex]/[itex]\delta[/itex]x)


I'm not going to attempt to type out me solving the integral because it would be extremely messy, as I am unfamiliar with syntax on this site.
I take the partial twice of ψ(x), and plug in the value they give for ∫x2|ψ|2:

-4hbar3a2 / 2mω0

This isn't correct, and I'm not too sure what I'm doing wrong. The negative doesn't make sense to me, but that's what the math is giving (the negative comes from squaring i in the momentum operator).

Any help is greatly appreciated.
 
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The syntax on this site is LaTex which is quite easy to use. Related to your problem, can you use the Virial Theorem ? Or you could go for an algebraic approach, because the average is computed in the ground state...
 
goolsby said:
Find the expectation value of (px)2, keeping in mind that ψ0(x) = A0e−ax2
where A0 = (2mω0/h)^1/4, and
<x2> = ∫x2|ψ|2dx = h_bar / 2mω0


<ψ(x)|px2|ψ(x)> = ∫ψ(x)(pop2)ψ(x) dx

pop = [hbar / i] ([itex]\delta[/itex]/[itex]\delta[/itex]x)


I'm not going to attempt to type out me solving the integral because it would be extremely messy, as I am unfamiliar with syntax on this site.
I take the partial twice of ψ(x), and plug in the value they give for ∫x2|ψ|2:

-4hbar3a2 / 2mω0

This isn't correct, and I'm not too sure what I'm doing wrong. The negative doesn't make sense to me, but that's what the math is giving (the negative comes from squaring i in the momentum operator).

Any help is greatly appreciated.

Can you explain to yourself why you are taking the partial twice? Are you missing any factors for the momentum operator?
 
The momentum operator squared is
-hbar2 δ2/δx2
 
goolsby said:
-4hbar3a2 / 2mω0

Except for the minus sign, this looks correct. Don't forget to substitute the expression for [itex]a[/itex].
 
Uh oh, I didn't substitute for a. Is this a common constant? They give what A0 is, but it goes away with the identity for <x2>.
 
Why compute tough integrals and derivatives, why not just convert p^2 into creation and annihilation operators?
 

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