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## Homework Statement

Find the flux through the equilateral triangle with corners at the points (1m,0,0), (0,1m,0), and (0,0,1m) in x,y,z space (measured in meters) for an electric field with magnitude E=6N/C pointing

**(a) in the z direction,****(b) parallel to the line y = x.**

## Homework Equations

Flux = EA;

Surface area of an equilateral triangle = (sqrt(3)/4)(a^2), where a = side of the triangle

Distance formula = sqrt(((x2-x1)^2) + (y2-y1)^2)

## The Attempt at a Solution

I approached this using the equation:

Flux = EA, where "E" is 6 N/C.

I tried solving for A by using the formula for the equilateral triangle area: ((sqrt(3)*s^2)/4), where s

is the side of the triangle. I solved for the side using the distance formula.

Now, with all things in consideration, I plugged everything in:

E=6

A=((sqrt(3)*(sqrt(2))^2)/4); s=sqrt(2);

E=6

A=(sqrt(3)/2) or .867

Flux = 3sqrt(3) or 5.1962

Now, I put this answer for question (a), and still got the wrong answer. What am I doing incorrectly?

Thank you kindly for the help.

Best,

Nicu