Find the flux through the equilateral triangle with corners at the points (1m,0,0), (0,1m,0), and (0,0,1m) in x,y,z space (measured in meters) for an electric field with magnitude E=6N/C pointing
- (a) in the z direction,
- (b) parallel to the line y = x.
Flux = EA;
Surface area of an equilateral triangle = (sqrt(3)/4)(a^2), where a = side of the triangle
Distance formula = sqrt(((x2-x1)^2) + (y2-y1)^2)
The Attempt at a Solution
I approached this using the equation:
Flux = EA, where "E" is 6 N/C.
I tried solving for A by using the formula for the equilateral triangle area: ((sqrt(3)*s^2)/4), where s
is the side of the triangle. I solved for the side using the distance formula.
Now, with all things in consideration, I plugged everything in:
A=(sqrt(3)/2) or .867
Flux = 3sqrt(3) or 5.1962
Now, I put this answer for question (a), and still got the wrong answer. What am I doing incorrectly?
Thank you kindly for the help.