Find the force of the rope on the block

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SUMMARY

The discussion focuses on calculating the force exerted by a rope on a block when a force 'P' is applied to the rope. The total mass of the system is the sum of the block's mass 'M' and the rope's mass 'm'. The derived equations show that the acceleration 'a' is equal to P divided by the total mass (M+m), and the force exerted on the block is calculated as mP/(M+m). The solution provided is confirmed as correct by other participants in the thread.

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ritwik06
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A block of mass 'M' is pulled along horizontal frictionless surface of a rope of mass 'm'. Force 'P' is applied at the end of rope. Find the force which the rope exerts on the block.

My attempt:
The total mass = M+m
Force P=(M+m)*a ------------ (i)
Force exerted on block = ma
a=P/(M+m)
Force on block=mP/(M+m)

Am i correct?
 
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Thread moved to homework. Based on your number of posts (not a newbie mistake), I'm giving a 0-point warning for posting a homework question in the general forums. Oh, and your answer looks correct to me.
 

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