- #1
vande060
- 186
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1. Homework Statement
A mass M1 = 10 kg rests on an incline of
angle θ = 60deg. Find the largest M2 such that no
accelerations occur.
a picture of the problem: http://s861.photobucket.com/albums/ab174/alkaline262/?action=view¤t=prob14.jpg
2. Homework Equations
f=ma
3. The Attempt at a Solution
here are the forces for m1(i think)
note: N is normal force T is string tension
(-a1,0) (0,N) (-m1gsin(60), -mg1cos(60)) (T1,0)
---------------------------------------------------
equations here for m1:
-m1a1 = T1 -m1gsin(60)
0 = N- m1gcos(60)
--------------------------------------------------
here are the forces for m2(i think)
(0,-a2) (0,T2) (0,-m2g)
-------------------------------------------------
equation for m2:
-m2a = T2 -m2g
--------------------------------------------------
all right now, i feel like i should be eliminating T, because it will be equal between the two equations:
T1 = -m1a + sin(60)m1g
- T2 = -m2a + m2g
-----------------------------
0 = -m1a + m2a +sin(60)m1g - m2g
okay i don't know what to do, or if what i have done is right, but i let a = 0 and solved for m2 here anyways :/
m2 = sin(60)m1
we know m1 = 10 so,
max m2 = 8.7 kg
any advice would be appreciated
A mass M1 = 10 kg rests on an incline of
angle θ = 60deg. Find the largest M2 such that no
accelerations occur.
a picture of the problem: http://s861.photobucket.com/albums/ab174/alkaline262/?action=view¤t=prob14.jpg
2. Homework Equations
f=ma
3. The Attempt at a Solution
here are the forces for m1(i think)
note: N is normal force T is string tension
(-a1,0) (0,N) (-m1gsin(60), -mg1cos(60)) (T1,0)
---------------------------------------------------
equations here for m1:
-m1a1 = T1 -m1gsin(60)
0 = N- m1gcos(60)
--------------------------------------------------
here are the forces for m2(i think)
(0,-a2) (0,T2) (0,-m2g)
-------------------------------------------------
equation for m2:
-m2a = T2 -m2g
--------------------------------------------------
all right now, i feel like i should be eliminating T, because it will be equal between the two equations:
T1 = -m1a + sin(60)m1g
- T2 = -m2a + m2g
-----------------------------
0 = -m1a + m2a +sin(60)m1g - m2g
okay i don't know what to do, or if what i have done is right, but i let a = 0 and solved for m2 here anyways :/
m2 = sin(60)m1
we know m1 = 10 so,
max m2 = 8.7 kg
any advice would be appreciated