Find the largest mass that can sit on an incline without accelerating

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SUMMARY

The discussion focuses on calculating the largest mass (M2) that can rest on a 60-degree incline without causing acceleration, given a mass (M1) of 10 kg. The solution involves analyzing forces acting on both masses, leading to the conclusion that the maximum M2 is approximately 8.7 kg. The equations of motion, including tension and gravitational components, are utilized to derive this result. The approach simplifies the problem by equating the gravitational force components along the incline.

PREREQUISITES
  • Understanding of Newton's second law (f=ma)
  • Basic knowledge of trigonometric functions, particularly sine and cosine
  • Familiarity with forces acting on inclined planes
  • Ability to solve simultaneous equations
NEXT STEPS
  • Study the effects of different incline angles on static friction and mass balance
  • Learn about tension in strings and its applications in physics problems
  • Explore advanced topics in dynamics, such as frictional forces on inclines
  • Investigate the role of gravitational components in multi-body systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for practical examples of force analysis on inclined planes.

vande060
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1. Homework Statement
A mass M1 = 10 kg rests on an incline of
angle θ = 60deg. Find the largest M2 such that no
accelerations occur.


a picture of the problem: http://s861.photobucket.com/albums/ab174/alkaline262/?action=view&current=prob14.jpg
2. Homework Equations

f=ma

3. The Attempt at a Solution

here are the forces for m1(i think)

note: N is normal force T is string tension

(-a1,0) (0,N) (-m1gsin(60), -mg1cos(60)) (T1,0)
---------------------------------------------------
equations here for m1:

-m1a1 = T1 -m1gsin(60)
0 = N- m1gcos(60)
--------------------------------------------------
here are the forces for m2(i think)

(0,-a2) (0,T2) (0,-m2g)

-------------------------------------------------
equation for m2:

-m2a = T2 -m2g
--------------------------------------------------

all right now, i feel like i should be eliminating T, because it will be equal between the two equations:

T1 = -m1a + sin(60)m1g
- T2 = -m2a + m2g
-----------------------------
0 = -m1a + m2a +sin(60)m1g - m2g

okay i don't know what to do, or if what i have done is right, but i let a = 0 and solved for m2 here anyways :/

m2 = sin(60)m1
we know m1 = 10 so,

max m2 = 8.7 kg

any advice would be appreciated

 
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an easier way would be taking the g components for m1 and since the (perpendicular-to-the-plane component) is balanced by normal reaction you can neglect it. Then the {along-the-inlinedplane(say gx) * mass1} should be equated to (mass2 * g) . and then get the answer easily...
ie
m1 * gx = m2 * g

And your answer seems to be right approximately.(i haven't exactly calculated)
 

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