- #1

vande060

- 186

- 0

**1. Homework Statement**

A mass M1 = 10 kg rests on an incline of

angle θ = 60deg. Find the largest M2 such that no

accelerations occur.

A mass M1 = 10 kg rests on an incline of

angle θ = 60deg. Find the largest M2 such that no

accelerations occur.

a picture of the problem: http://s861.photobucket.com/albums/ab174/alkaline262/?action=view¤t=prob14.jpg

**2. Homework Equations**

f=ma

f=ma

**3. The Attempt at a Solution**

here are the forces for m1(i think)

note: N is normal force T is string tension

(-a1,0) (0,N) (-m1gsin(60), -mg1cos(60)) (T1,0)

---------------------------------------------------

equations here for m1:

-m1a1 = T1 -m1gsin(60)

0 = N- m1gcos(60)

--------------------------------------------------

here are the forces for m2(i think)

(0,-a2) (0,T2) (0,-m2g)

-------------------------------------------------

equation for m2:

-m2a = T2 -m2g

--------------------------------------------------

all right now, i feel like i should be eliminating T, because it will be equal between the two equations:

T1 = -m1a + sin(60)m1g

- T2 = -m2a + m2g

-----------------------------

0 = -m1a + m2a +sin(60)m1g - m2g

okay i don't know what to do, or if what i have done is right, but i let a = 0 and solved for m2 here anyways :/

m2 = sin(60)m1

we know m1 = 10 so,

max m2 = 8.7 kg

any advice would be appreciated

here are the forces for m1(i think)

note: N is normal force T is string tension

(-a1,0) (0,N) (-m1gsin(60), -mg1cos(60)) (T1,0)

---------------------------------------------------

equations here for m1:

-m1a1 = T1 -m1gsin(60)

0 = N- m1gcos(60)

--------------------------------------------------

here are the forces for m2(i think)

(0,-a2) (0,T2) (0,-m2g)

-------------------------------------------------

equation for m2:

-m2a = T2 -m2g

--------------------------------------------------

all right now, i feel like i should be eliminating T, because it will be equal between the two equations:

T1 = -m1a + sin(60)m1g

- T2 = -m2a + m2g

-----------------------------

0 = -m1a + m2a +sin(60)m1g - m2g

okay i don't know what to do, or if what i have done is right, but i let a = 0 and solved for m2 here anyways :/

m2 = sin(60)m1

we know m1 = 10 so,

max m2 = 8.7 kg

any advice would be appreciated