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Find the length of curve r=1-cos (tita)

  1. Jul 15, 2006 #1
    find the length of curve r=1-cos (tita)

    pls help to formulat an eqn for f(x,y)

  2. jcsd
  3. Jul 15, 2006 #2


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    Gold Member

    Hello teng,

    the curve is given in polar coordinates.

    [tex]\theta \, \mapsto \, (r(\theta)\cos(\theta),r(\theta)\sin(\theta)) [/tex]

    with [tex]\theta_1\leq\theta\leq\theta_2[/tex]

    You can make use of the appropriate formula to calculate the length L.

    [tex]L=\int_{\theta_1}^{\theta_2}\sqrt{(r'(\theta))^2+r^2(\theta)} \, d\theta[/tex]


    Last edited: Jul 15, 2006
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