Find the Max Compression of a 2.80kg Block

AI Thread Summary
A 2.80 kg block with an initial velocity of 1.2 m/s collides with a spring, while experiencing friction with a coefficient of 0.5. The initial kinetic energy (KEi) is calculated to be 2.02 J, and the frictional force is determined to be 13.72 N. The discussion highlights the need to correctly apply energy conservation principles, specifically equating initial kinetic energy to the work done against friction and the potential energy stored in the spring. Participants emphasize avoiding incorrect units by mixing Newtons and Joules in calculations. The quadratic formula is suggested as a method to solve for maximum compression in the spring.
physics333
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A block having a mass of 2.80 kg is given an initial velocity of 1.2m/s when it collides with a spring. The constant force of friction acts between the block and the surface with (mu sub k=0.5) and the force constant of the spring is k=100N/m. What is the maximum compression?

I've been stuck on the problem for a while.
Workfriction + KEi + PEi = KE + PE

KEi =2.02J
fk =13.72
KE=0
PEi =0

therefore (13.72 N + 2.02 J)/ 50N/m = x^2

Is this equation right? If so, how do I find x?
I tried to work it but I can't figure out how to add Newtons and joules divided by N/m and end up with x in meters...

Please help
 
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1N=1kgm/s2 ---- remember F=ma?
1J=1kgm2/s2 ----- remember W=Fx?
 
I still need more information...I'm not as smart as some as you. Someone get me started and I can figure it out...
Thanks
 
Originally posted by physics333

therefore (13.72 N + 2.02 J)/ 50N/m = x^2

There should be massive alarms going off when you get N+J in a physics problems.

If you put your equation together right, this should be easy:

KEi=Workfriction+PEspring
or
1/2mv02=ffrictionx+1/2kx2

Just remember the quadratic formula.
 

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