Find the mean number density of particles in the stellar atmosphere.

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SUMMARY

The discussion focuses on calculating the mean number density of particles in a stellar atmosphere using the mean radiation pressure of 0.33 N m-2 and mean gas pressure of 8300 N m-2. The relevant equation for radiation pressure is given as Radiation pressure = (4σT4)/(3c), where σ = 5.67 x 10-8. The calculated effective temperature is 6016K, leading to a subsequent calculation of radiation pressure at twice the effective temperature, resulting in a value of 5.28 Pa.

PREREQUISITES
  • Understanding of radiation pressure and its formula
  • Knowledge of gas laws, specifically the ideal gas law (pV=nRT)
  • Familiarity with thermodynamic concepts, particularly temperature and pressure relationships
  • Basic proficiency in algebra for manipulating equations
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  • Study the derivation and applications of the radiation pressure equation
  • Learn about the ideal gas law and its implications in astrophysics
  • Research the concept of effective temperature in stellar atmospheres
  • Explore advanced thermodynamics related to stellar physics
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Astronomy students, astrophysicists, and anyone involved in stellar physics or thermodynamics will benefit from this discussion.

Jon.G
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Homework Statement


The atmosphere of a star has a mean radiation pressure of 0.33 N m-2and a mean gas pressure of 8300 N m-2. Calculate:
a) the mean number density of particles in the stellar atmosphere, and
b) the radiation pressure in a stellar atmosphere with twice the effective temperature.

Homework Equations


Radiation pressure = \frac{4 \sigma T^{4}}{3c} where σ = 5.67*10-8


The Attempt at a Solution


a) From the radiation pressure equation, I get T=6016K
and I'm not sure where to go from here. I would have thought to have used pV=nRT, but then that bring volume into the equation. I know it's probably really simple and is just something I am forgetting, but I just can't figure it out :/


b) Multiply the given value (0.33) by 16, as it is T4
5.28Pa


Thanks
 
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Jon.G said:
I would have thought to have used pV=nRT, but then that bring volume into the equation.
You wish to find n/V, right?
 
:S
Yes I do.
... I don't even know what to say, how could I not see that?

Thanks
 

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