- #1
coolusername
- 36
- 0
The position function of a particle is given by r(t)=⟨−5t2,−4t,t2+1t⟩.
At what time is the speed minimum?
I found the speed function by taking the magnitude of the velocity which is
lv(t)l = sqrt(108t^2 +4t + 17)
I then took the derivative of the speed to find the critical point. However, I'm always left with a negative time.
d/dt lv(t)l = (104t + 2)/sqrt(104t^2 +4t+17)
The only way to find the minimum is when the numerator is 0. But when I isolate t, it always equals a negative number.
Is my approach correct?
Any help would be appreciated. Thanks!
At what time is the speed minimum?
I found the speed function by taking the magnitude of the velocity which is
lv(t)l = sqrt(108t^2 +4t + 17)
I then took the derivative of the speed to find the critical point. However, I'm always left with a negative time.
d/dt lv(t)l = (104t + 2)/sqrt(104t^2 +4t+17)
The only way to find the minimum is when the numerator is 0. But when I isolate t, it always equals a negative number.
Is my approach correct?
Any help would be appreciated. Thanks!