Find the net electric field these charges produce

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SUMMARY

The discussion focuses on calculating the net electric field produced by two point charges, q1 = -6.15 nC and q2 = -10.5 nC, separated by 25.0 cm. The electric field is calculated using the formula E = ke * Q / r², where ke = 9 x 10⁹ N m²/C². The correct approach involves recognizing the vector nature of electric fields; the field from q1 points to the left and that from q2 points to the right, leading to a net electric field of 11910 N/C to the right at point A. The sign of the charges must be considered, as the direction of the electric field depends on whether the charge is positive or negative.

PREREQUISITES
  • Understanding of electric fields and point charges
  • Familiarity with the formula E = ke * Q / r²
  • Knowledge of vector addition in physics
  • Concept of electric force on charged particles
NEXT STEPS
  • Study the concept of electric field lines and their representation
  • Learn about the superposition principle for electric fields
  • Explore the effects of multiple charges on electric fields
  • Investigate the relationship between electric fields and forces on test charges
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding electric fields and forces between charged particles.

yaro99
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Homework Statement


Two point charges q1 = -6.15 nC, and q2 = -10.5 nC are separated by 25.0 cm (see figure below).
21-p-031-alt.gif


(a) Find the net electric field these charges produce at point A

(b) Find the net electric field these charges produce at point B

(c) What would be the magnitude and direction of the electric force this combination of charges would produce on a proton at A?


Homework Equations


E=ke*Q/r2



The Attempt at a Solution



I got the correct answer for (b), but got an incorrect answer for (a) using the same method.

E = (ke*Q)/(r2)
ƩE = 9*109 * [(6.15*10-9)/(0.152) + (10.5*10-9)/(0.102)] = 11910 N/C to the right
 
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yaro99 said:

Homework Statement


Two point charges q1 = -6.15 nC, and q2 = -10.5 nC are separated by 25.0 cm (see figure below).
21-p-031-alt.gif


(a) Find the net electric field these charges produce at point A

(b) Find the net electric field these charges produce at point B

(c) What would be the magnitude and direction of the electric force this combination of charges would produce on a proton at A?


Homework Equations


E=ke*Q/r2



The Attempt at a Solution



I got the correct answer for (b), but got an incorrect answer for (a) using the same method.

E = (ke*Q)/(r2)
ƩE = 9*109 * [(6.15*10-9)/(0.152) + (10.5*10-9)/(0.102)] = 11910 N/C to the right

The electric field is a vector quantity, it has direction. What are the directions of the electric fields due to the individual charges at point (a)?

ehild
 
ehild said:
The electric field is a vector quantity, it has direction. What are the directions of the electric fields due to the individual charges at point (a)?

ehild

Ah, q1 is pointing to the right and q2 to the left, so I subtract the q2 field from the q1 field.

One question: Do I include the +/- charges in my equation? ie. would my values for q1 and q2 in the equation be negative since they are both negative charges?
I got the write answer by just writing the absolute value of my (negative) answer.

edit: completed part (c) with no problems.
 
Yes, you need to include the sign of the charge. In case of a negative charge, the electric field points toward the charge. If it is positive, the electric field points away from it. So the electric field due to q1 points to the left, that of q2, points to the right. As the field due to q2 is of greater magnitude, the net electric field points to the right, it is positive.

ehild
 

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