Find the net electric field these charges produce

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Homework Help Overview

The discussion revolves around calculating the net electric field produced by two point charges, q1 and q2, both of which are negative. The charges are separated by a specified distance, and the participants are tasked with determining the electric field at two different points, A and B, as well as the force on a proton at point A.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the method for calculating the electric field using the formula E=ke*Q/r², and some question the direction of the electric fields produced by the individual charges at point A. There is also a discussion about whether to include the signs of the charges in the calculations.

Discussion Status

There is an ongoing exploration of the correct approach to determine the net electric field at point A, with some participants successfully completing part (c) of the problem. Guidance has been provided regarding the direction of the electric fields and the importance of considering the signs of the charges.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. The discussion reflects uncertainty about the application of charge signs in calculations.

yaro99
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Homework Statement


Two point charges q1 = -6.15 nC, and q2 = -10.5 nC are separated by 25.0 cm (see figure below).
21-p-031-alt.gif


(a) Find the net electric field these charges produce at point A

(b) Find the net electric field these charges produce at point B

(c) What would be the magnitude and direction of the electric force this combination of charges would produce on a proton at A?


Homework Equations


E=ke*Q/r2



The Attempt at a Solution



I got the correct answer for (b), but got an incorrect answer for (a) using the same method.

E = (ke*Q)/(r2)
ƩE = 9*109 * [(6.15*10-9)/(0.152) + (10.5*10-9)/(0.102)] = 11910 N/C to the right
 
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yaro99 said:

Homework Statement


Two point charges q1 = -6.15 nC, and q2 = -10.5 nC are separated by 25.0 cm (see figure below).
21-p-031-alt.gif


(a) Find the net electric field these charges produce at point A

(b) Find the net electric field these charges produce at point B

(c) What would be the magnitude and direction of the electric force this combination of charges would produce on a proton at A?


Homework Equations


E=ke*Q/r2



The Attempt at a Solution



I got the correct answer for (b), but got an incorrect answer for (a) using the same method.

E = (ke*Q)/(r2)
ƩE = 9*109 * [(6.15*10-9)/(0.152) + (10.5*10-9)/(0.102)] = 11910 N/C to the right

The electric field is a vector quantity, it has direction. What are the directions of the electric fields due to the individual charges at point (a)?

ehild
 
ehild said:
The electric field is a vector quantity, it has direction. What are the directions of the electric fields due to the individual charges at point (a)?

ehild

Ah, q1 is pointing to the right and q2 to the left, so I subtract the q2 field from the q1 field.

One question: Do I include the +/- charges in my equation? ie. would my values for q1 and q2 in the equation be negative since they are both negative charges?
I got the write answer by just writing the absolute value of my (negative) answer.

edit: completed part (c) with no problems.
 
Yes, you need to include the sign of the charge. In case of a negative charge, the electric field points toward the charge. If it is positive, the electric field points away from it. So the electric field due to q1 points to the left, that of q2, points to the right. As the field due to q2 is of greater magnitude, the net electric field points to the right, it is positive.

ehild
 

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