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## Homework Statement

The two forces F1 and F2 (shown in the figure) (i attached the figure hopefully I did it correctly) act on a 27.0 kg object on a frictionless tabletop. If F1=10.2N and F2= 16.0N, find the net force on the object and its acceleration for a and b

## Homework Equations

F=ma

## The Attempt at a Solution

If I'm approaching this correctly I believe its a simple vector addition problem?

for a I have:

x= -10.2

y= -16.0

this vector is = SQRT(-10.2

^{2}+ -16.0

^{2}) = 18.97N

F=ma

19.97 = 27.0kg (a)

a= 0.70 m/s

^{2}

For b I have:

F2: x=0 y=16

F1: x=cos30 (10.2) = 8.8 y= sin30 (10.2) = -5.1

adding the x's together = 8.8

adding the y's together = 10.9

finding the vector= SQRT(8.8

^{2}+ 10.9

^{2}) = 14.0N

F=ma

14.0 = 27.0 kg (a)

a= 0.52 m/s

^{2}

Does this look correct?? Or did I even approach this correctly??

Thanks!