Find the outward flux of the field - Green's Theorem

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SUMMARY

The discussion focuses on calculating the outward flux of the vector field F = (3xy - x/(1+y²))i + (e^x + tan⁻¹y)j across the cardioid defined by r = a(1 + cosθ), where a > 0. The divergence of the field is determined using the formula div F = (∂M)/∂x + ∂N/∂y. The correct limits of integration for the double integral are established as θ ranging from 0 to 2π and r from 0 to a(1 + cosθ), necessitating the conversion of div F into polar coordinates for accurate computation.

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Homework Statement



(Q) Find the outward flux of the field

F=(3xy-x/(1+y^2 ))i+(e^x+tan^(-1)⁡y )j

across the cardioid r=a(1+cos⁡θ), a>0.



Homework Equations



div F = (∂M )/∂x+∂N/∂y


The Attempt at a Solution



I could easily set up the double integral which is:

∬▒3 r^2 sin⁡θ dA

However, I am unsure as to how to determine the limits to be used.
Please help. Thank-you.
 
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?? The limits of integration ARE the cardioid, of course: [itex]\theta[/itex] going from 0 to [itex]2\pi[/itex], r from 0 to a(1+ cos([itex]\theta[/itex])). Since that is given in polar coordinates, it might be best to convert div F to polar coordinates.
 
Yes but...

Usually, the limits of r ranges from a constant value to another constant value of r. Why do we, in this case simply plug in the equation of the cardioid?

Thanks a lot for your help and support!:smile:
 

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