1. The problem statement, all variables and given/known data Find the point(s) on the parabola x= y^2-8y+18 closest to (-2,4) 2. Relevant equations 3. The attempt at a solution Using the distance formula I found that d^2 = y^4 - 16y^3 + 105y^2 - 328y + 416 after differentiating I have 2d' = 4y^3 - 48y^2 + 210y -328 I'm not sure what to do now, or what I may have done wrong, any help is appreciated. Thanks!