Find the resistance of the coil

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SUMMARY

The discussion centers on calculating the resistance of a metal coil in a water heater connected to a 24-V power supply. To determine the resistance, the user needs to calculate the power required to heat 270 mL of water from 20°C to boiling point in 70 seconds. The relevant formula is R = dV/I, where dV is the voltage and I is the current. The user suggests using the thermal energy equation Q = mc*dT to find the energy required, which will then allow for the calculation of current and, subsequently, resistance.

PREREQUISITES
  • Understanding of Ohm's Law (R = V/I)
  • Knowledge of thermal energy calculations (Q = mc*dT)
  • Basic principles of electricity and power (P = IV)
  • Familiarity with units of measurement (voltage, current, resistance)
NEXT STEPS
  • Calculate the thermal energy required to heat 270 mL of water using Q = mc*dT.
  • Determine the power (in watts) required for the heating process.
  • Use the power value to find the current (I) using the formula P = IV.
  • Substitute the values into R = dV/I to find the resistance of the coil.
USEFUL FOR

Students studying physics, electrical engineers, and anyone interested in understanding the principles of electrical resistance in heating elements.

Cisneros778
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Homework Statement


A water heater consisting of a metal coil that is connected across the terminals of a 24-V power supply is able to heat 270 mL of water from room temperature (20°C) to boiling point in 70 s. What is the resistance of the coil? (When entering units, use ohm for Ω.)


Homework Equations


R = dV/I


The Attempt at a Solution


I am not sure how to approach this one. I think the temperature is throwing me off. I have V so I am trying to find I. I was thinking of using I = dQ/dT since I have the time interval, but finding Q isn't possible unless I am given values for charges. I almost want to use Q = mc*dT but Q here is thermal energy so I'm back to square one.
 
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Your thought about thermal energy looks promising. How much energy is required to heat the given amount of water by the stated amount? If it's done in the stated amount of time, what's the power (watts) involved?
 

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