Find the slope of the tangent line to the give polar curve at the point specified by the value of theta
R = 1/θ, θ = π
Slope of a polar equation is (dR/dθsinθ+Rcosθ/dR/dθcosθ-Rsinθ)
The Attempt at a Solution
Using my calculator, I plugged π for θ, -.101 for DR/Dtheta (after differentiating R) and R = 1/π
I got π/12 as my answer, but the correct answer is -π. Why am I off by a factor of 12?