Find the slope of the tangent line

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Homework Help Overview

The discussion revolves around finding the slope of the tangent line to the curve defined by the equation sqrt(4x+2y) + sqrt(1xy) = 9.72 at the point (6,3). The subject area is calculus, specifically focusing on derivatives and implicit differentiation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to find the derivative to determine the slope of the tangent line. There is an exploration of whether the equation should be rearranged to express y in terms of x, with some participants expressing difficulty in this approach. Implicit differentiation is suggested as an alternative method, leading to further questions about the complexity of the differentiation process.

Discussion Status

Participants are actively engaging with the problem, with some offering guidance on using implicit differentiation instead of rearranging the equation. There is acknowledgment of the challenges faced during the differentiation process, and one participant reports correcting their earlier mistake after receiving feedback.

Contextual Notes

There is mention of the complexity of the differentiation process and the potential for confusion when applying the chain and product rules. Participants are navigating through the implications of their approaches and the assumptions they are making about the function's form.

cal.queen92
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Homework Statement




Find the slope of the tangent line to the curve:

sqrt(4x+2y) + sqrt(1xy) = 9.72

at the point (6,3)


Homework Equations




Derivative laws


The Attempt at a Solution



the slope of the tangent line to a curve is the Derivative of the function of the curve, so I need to find the derivative, right?

Now, to obtain the derivative, I feel as if I need to have the function as a function of y in terms of x. (f(x) = ... or y=x...). But every time I attempt to put the equation in that form I get stuck!

I tried squaring both sides of the equation, ending up with something ugly.

I also tried the following:

sqrt(4x+2y) + sqrt(1xy) = 9.72 --> sqrt(4x+2y) = 9.72 - sqrt(1xy)

and then squared both sides again and ended up with something ugly again.

Any Ideas?

Thanks!
 
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cal.queen92 said:
the slope of the tangent line to a curve is the Derivative of the function of the curve, so I need to find the derivative, right?

Right!

Now, to obtain the derivative, I feel as if I need to have the function as a function of y in terms of x.

Wrong!

You don't have to have that, and in this case it isn't even desirable. Use implicit differentiation instead.
 
OOOOkayy i completely forgot about implicit differentiation... I've tried it now and am not getting it right, The differentiating process is extremely long, should it be? I am getting lost in my work it is so long.
 
No, it shouldn't be long at all. Rewrite the relation as follows.

(4x+2y)^{1/2}+(xy)^{1/2}=9.72

You'll need to apply the Chain Rule to both terms on the left side. In addition to that you'll need the Product Rule for the second one. Don't forget that the derivative of the right side is zero.
 
Yes, I used the chain rule and product rule and ended up with:

dy/dx = ((-xy^2 * sqrt(4x+2y)) -4)/ (2 + (yx^2 * sqrt(4x+2y))

and then when I filled in the values of the point i got an answer of:

(-54sqrt(30)-4)/(2+108sqrt(30)) which is wrong...

perhaps if i show you my first step:

((1/2)((4x+2y)^(-1/2))(4+2dy/dx)) + ((1/2)((xy)^ and I have just found my mistake...

Thank you very much! The answer is now right...
 

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