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Find the vertical distance the car has fallen

  1. Jun 9, 2013 #1
    1. A toy car moving at a constant speed of 3m/s on a horizontal road, heds toward and falls off a cliff. As it falls, it is notices that the car's velocity is directed 80 degrees below the horizontal when the caar has dropped an unknown vertical distance below the top of the cliff. Find the vertical distance the car has fallen at this point in the motion.



    2. vx=voxcosθ
    vy=voysinθ-gt^2




    3. Δx=3cos80t
    Δy=-1/2gt^2
    two variables: y and t.
    should i use this equation instead:
    Δy=[-g(Δx/cosθ)^2]/2 + Δxtanθ?
    or am i using the wrong approach?
     
  2. jcsd
  3. Jun 9, 2013 #2

    tiny-tim

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    hi jenjo! welcome to pf! :smile:

    (try using the X2 and X2 buttons just above the Reply box :wink:)
    no, ∆x = 3t :redface:

    start again …

    you need to find vx and vy as functions of t,

    then find t when that's 80°,

    then find y :smile:
     
  4. Jun 9, 2013 #3

    haruspex

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    What, precisely, and in the context of this question, are v0 and θ in that equation?
     
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