1. A toy car moving at a constant speed of 3m/s on a horizontal road, heds toward and falls off a cliff. As it falls, it is notices that the car's velocity is directed 80 degrees below the horizontal when the caar has dropped an unknown vertical distance below the top of the cliff. Find the vertical distance the car has fallen at this point in the motion. 2. vx=voxcosθ vy=voysinθ-gt^2 3. Δx=3cos80t Δy=-1/2gt^2 two variables: y and t. should i use this equation instead: Δy=[-g(Δx/cosθ)^2]/2 + Δxtanθ? or am i using the wrong approach?