1. The problem statement, all variables and given/known data Given a square and the respective distension tensor, ε, find the position on his vortices after the transformation. ε = 0.1.....0.25 .....0.25.....0.1 2. Relevant equations 3. The attempt at a solution I got kind of lost in this question. I started thinking that maybe a vortic at the coordinates (a,b) would later be at the position (a',b') given by: (a',b') = (a,b)ε This got me some weird results tho, which led me to believe it was wrong. I later tried to solve it using each component of the tensor alone. I know that the components of the diagonal give me the elongation, therefore I used them to find the positions of the vortices after the elongation. The problem came when I had to deal with the distortion. How can I find the position of the vortices there? I managed to find the position of the vortices that were at either the x axis or y axis, using trigonometry sin(εxy)=b'/L , where L is the length of the square after the elongation. My problem now rests with finding the position of the vortix at (L,L). Using trigonometry I found that the size of the diagonal,D, after the distortion was: D = Lcos(π/4-εxy) Since the vortix will still have an y coordinate equal to the x coordinate after the distortion I can say that: 2A^2=D^2 , where A will be the position of the vortix after the distortion. I think my way of solving the problem is correct, however I can't help but think there's a better way... If someone could throw me some light I'd appreciate.