(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

a constant force Fa of magnitude 85.0 N is applied to a 4.0 kg shoe box at angle φ = 53.0°, causing the box to move up a frictionless ramp at constant speed. How much work is done on the box by Fa when the box has moved through vertical distance h = 0.45 m?

heres the picture to explain where the phi comes from http://edugen.wiley.com/edugen/courses/crs1650/art/qb/qu/c07/pict_7_32.gif

2. Relevant equations

W=F dot D

or W = FDcostheta

3. The attempt at a solution

i know that if an object is going at constant speed it's net force is zero

i tried solving for D which gave me .45/sintheta

then i got y comp of the weight force = 4gsinthet

the x comp of the wieght cut the phi angle in two = 53 - theta

and using Fa and angle (53-thet) i got the force that balance the 4g sin = 85sin(53 - thet)

then i used 4g sinthet = 85sin(53 - thet) to find theta because the net force is zero

i then put the theta i got into the D equation above.

I then found the x and y components of D and the x and y compnents of F using the angle( 53-thet) and did the dot product of that which came out to be 59.51455753 J

and it's wrong....

the answer is 17.658 J...supposedly

can someone tell me what i'm doing wrong? am i using the wrong angle or am i just going abot the problem wrong from the beginning? help please

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# Homework Help: Find the work done on a box on an inclined plane

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