Find Value of tan φ of Reaction Force | Isaac Physics

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SUMMARY

The discussion focuses on calculating the value of tan φ, where φ represents the angle made by the line of action of the reaction force at a hinge above the horizontal. The problem involves a uniform trapdoor with a mass of 4.0 kg, held open at an angle of θ = 60° to the horizontal, under the influence of gravitational field strength g = 9.81 m/s². Participants emphasize the necessity of establishing torque balance and correctly interpreting the simultaneous equations related to the vertical and horizontal components of forces acting on the trapdoor.

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ephphatha16
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Find the value of tan φ to 2 sf where φ is angle made by line of action of reaction force at hinge above horizontal.
https://isaacphysics.org/questions/trapdoor_num
Part B Angle of reaction force

Homework Equations


  • Mass of uniform trapdoor: m=4.0kgm=4.0kg
  • The trapdoor is held open making an angle θ=60∘θ=60∘ to the horizontal.
Information assumed
- Magnitude of the gravitational field strength, g=9.81ms−2

The Attempt at a Solution


[/B]Don't know how to move on with this simultaneous equation

Fcosθ + Nsinθ=mg
Fsinθ = Ncosθ
 

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ephphatha16 said:
Fcosθ + Nsinθ=mg
Fsinθ = Ncosθ
Shouldn't some of those angles be φ?
You will also need to consider torque balance.
 
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haruspex said:
Shouldn't some of those angles be φ?
You will also need to consider torque balance.
Yeah true

Fcos θ + Nsin φ = mg
F sin θ = N cos φ

But I don't know what values to plug in ... is the first equation about vertical component and the second equation about horizontal component?
 
ephphatha16 said:
I don't know what values to plug in
φ will not depend on m or g. You are given a value for θ.
ephphatha16 said:
is the first equation about vertical component and the second equation about horizontal component?
Yes, but you have three unknowns, F/mg, N/mg and φ. You need a torque balance equation.
 
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