Torque around a curb - bicyle forces problem

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Homework Help Overview

The problem involves analyzing the forces acting on a bicycle tire as it attempts to go over a curb. It specifically focuses on determining the angle at which an applied force results in the smallest magnitude needed to lift the tire over the curb, considering the tire's radius and the curb's height.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss separating the applied force into components and calculating torques about the pivot point where the tire contacts the curb. Questions arise regarding the reasoning behind the angle that minimizes the force and the relationship between the applied force and torque.

Discussion Status

Participants are exploring different geometric and torque-related approaches to determine the angle of the applied force. Some guidance has been offered regarding the relationship between the angle and the geometry of the situation, but there is no explicit consensus on the best method yet.

Contextual Notes

There is some uncertainty regarding the definitions of terms used, such as the applied force and its relationship to torque. Participants are also navigating through the complexity of the problem, which involves multiple variables like the height of the curb and the radius of the tire.

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Homework Statement


A bicycle tire with radius R is attempting to go over a curb of height h. If a force F is applied to the center of the wheel, at an angle θ above the horizontal, what angle results in a force with the smallest magnitude to raise the wheel over the curb?

Homework Equations


ƩT=0
ƩF=0 (?)

The Attempt at a Solution


Having done this problem for a solely horizontal force, I tried to copy the same idea, but separated F into x and y components (giving Fcosθ and Fsinθ). The distance to Fg and Fy was √(2Rh-h^2), and the distance to Fx is R-h. After doing this, Fg is + and the other two are negative. The net torque equation I get it
0=mg*√(2Rh-h^2)-Fy*√(2Rh-h^2)-Fx*(R-h)
I don't know where to go from here (or if this is correct).
 
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Try thinking about the problem this way.

First, Assume the tire pivots about the point where the tire makes contact with the curb. The torque due to gravity is your first term mg*√(2Rh-h^2). Now the angle of the minimum force will be where the force is perpendicular to the line from the center of the wheel to the pivot point.

Try setting FR = mg*√(2Rh-h^2) to find the force.
 
How do I know that the angle perpendicular is the smallest? Also by FR do you mean the applied force? Sorry! I've been on this problem so long I don't even know what I'm thinking anymore
 
FR is force X tire radius. You will get maximum torque when the force is perpendicular to the line from the tire center to the point of pivot, i.e. where the tire meets the curb. You can probably use geometry to fine the perpendicular angle.
 
Oh! I understand. So to figure out the angle, it's probably easier to use geometrical arguments than net torque?
 
I would think so. The angle would be a function of h and R. I think it would involve a arctan function probably. The force will be in terms of h, R, m, and g.
 
The answer provided gives an arcsin function with just r and h, but I'm going to try it for a bit and see what I can get.
 
I think you are correct. As I look at it, I see something like arcsin (R-h)/R -90 or something similar.
 
Yes! That worked out. Thank you so much!
 

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