1. The problem statement, all variables and given/known data A bicycle tire with radius R is attempting to go over a curb of height h. If a force F is applied to the center of the wheel, at an angle θ above the horizontal, what angle results in a force with the smallest magnitude to raise the wheel over the curb? 2. Relevant equations ƩT=0 ƩF=0 (?) 3. The attempt at a solution Having done this problem for a solely horizontal force, I tried to copy the same idea, but separated F into x and y components (giving Fcosθ and Fsinθ). The distance to Fg and Fy was √(2Rh-h^2), and the distance to Fx is R-h. After doing this, Fg is + and the other two are negative. The net torque equation I get it 0=mg*√(2Rh-h^2)-Fy*√(2Rh-h^2)-Fx*(R-h) I don't know where to go from here (or if this is correct).