Find vector ##x## and ##y## by considering the vector diagram

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SUMMARY

The discussion focuses on finding vectors ##\vec x## and ##\vec y## using vector diagrams and algebraic manipulation. The primary solution presented is ##\vec x = -\vec a + \vec d - \vec c## and ##\vec y = -\vec d + \vec c - \vec b##. An alternative approach is suggested, emphasizing the importance of identifying loops that contain ##\vec x## but not ##\vec y## for potential optimization. The consensus is that while the current solution is effective, exploring different loops can enhance problem-solving efficiency.

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chwala
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Homework Statement
Find vector ##x## and ##y## by considering the vector diagram
Relevant Equations
Vectors
This is the problem,
1629341898405.png


I managed to solve it, i just want to check if there is an alternative approach. Find my solution below;

##\vec x= -\vec a-\vec b-\vec y##
##\vec y= -\vec d+\vec c-\vec b## therefore,
##\vec x= -\vec a-\vec b+\vec d-\vec c+\vec b##
##\vec x= -\vec a+\vec d-\vec c##
 
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Your answer seems the unique way to express them by a b c d.
 
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chwala said:
Homework Statement:: Find vector ##x## and ##y## by considering the vector diagram
Relevant Equations:: Vectors

This is the problem,
View attachment 287753

I managed to solve it, i just want to check if there is an alternative approach. Find my solution below;

##\vec x= -\vec a-\vec b-\vec y##
##\vec y= -\vec d+\vec c-\vec b## therefore,
##\vec x= -\vec a-\vec b+\vec d-\vec c+\vec b##
##\vec x= -\vec a+\vec d-\vec c##
You could improve the solution slightly by using a different loop to find ##\vec x##.

Can you see the loop containing ##\vec x## but not contianing ##\vec y##?
 
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Steve4Physics said:
You could improve the solution slightly by using a different loop to find ##\vec x##.

Can you see the loop containing ##\vec x## but not contianing ##\vec y##?
Hey, I will look at it over the weekend...cheers
 
It would just be direct from the diagram...

##\vec x= -\vec a+\vec d-\vec c##

1630720937379.png
 
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chwala said:
It would just be direct from the diagram...

##\vec x= -\vec a+\vec d-\vec c##
Yes. It doesn't save much work in this particular problem, but it's still a good idea to look for the 'best' loop(s).
 
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