# Find voltages across resistors using voltage division

cnh1995
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You have the value of Va-VG and VB-VG. What will be VA-VB then?

You have the value of Va-VG and VB-VG. What will be VA-VB then?
Va-Vg=8V and Vb-Vg=2.5V? Using those equations, solve for Va-Vb and get 5.5V?

cnh1995
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Va-Vg=8V and Vb-Vg=2.5V? Using those equations, solve for Va-Vb and get 5.5V?
Exactly! If you assume VG=0, you'll get absolute values of Va and Vb as 8V and 2.5V. The difference is 5.5V.

Marcin H
cnh1995
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See? Wasn't that difficult!

See? Wasn't that difficult!
It makes a little more sense now, but not 100%. The math makes sense, but the other stuff is still a bit confusing. Oh well. Thanks for the help!

cnh1995
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The math makes sense, but the other stuff is still a bit confusing.
What do you find confusing? A circuit works with potential "differences". In your circuit, the source is of 10V. Now, all the voltages present in the circuit are due to that 10V source, right? There is always a reference point in a circuit, called 'ground'. All the voltages are measured w.r.t ground. The choice of ground is ours i.e. we can assume it at any point. Here, for the sake of convenience, ground is assumed at the -ve terminal of the 10V source. Now, when you say voltage across 100 ohm is 8V, it is the potential difference between ground and point A, right? And 2.5V is the potential difference between ground and B. Since ground is common to both the resistors, you can say, A is 8V above the ground potential and B is 2.5V above the ground potential. It's like saying building A is 8m tall and building B is 2.5m tall( building height is measured from common ground, isn't it?). So, differene in height between buildings A and B would be 5.5m, right? Similarly, voltage between A and B is 5.5V.

Last edited:
Marcin H and Merlin3189
Since ground is common to both the resistors, you can say, A is 8V above the ground potential and B is 2.5V above the ground potential.
That's the part that kinda bugged me. I always think of voltage/potential across something or between 2 points. I wasn't sure why you can just say point A is at this potential and point B is at that potential. But that makes sense now. the potential in that portion of the wire is 8V so that means point A is at 8V right? Same for point B?

cnh1995
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the potential in that portion of the wire is 8V so that means point A is at 8V right? Same for point B?
Yes, assuming VG=0V.

Marcin H