Find ##z## in the form ##a+bi## under Complex Numbers

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The discussion focuses on finding the complex number ##z## in the form ##a + bi##. For part (a), the calculation yields ##z = \dfrac{4}{5} + \dfrac{3}{5}i##. Part (b) emphasizes the importance of understanding the Argand plane for complex numbers. In part (c), the modulus of ##z## is confirmed to be 1, while the modulus of ##z - z^*## is incorrectly stated as ##\frac{6}{5}i##, which is clarified to be simply ##\dfrac{6}{5}## as it must be a real number. The discussion highlights the need for accuracy in complex number calculations.
chwala
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Homework Statement
see attached
Relevant Equations
Complex numbers
1646184520481.png


For part (a),
##z##=##\dfrac {3+i}{3-i}## ⋅##\dfrac {3+i}{3+i}##
##z##=##\dfrac {4}{5}##+##\dfrac {3}{5}i##

part (b) no problem as long as one understands the argand plane...

For part (c)
Modulus of ##z=1##
and Modulus of ##z-z^*##=##\frac{6}{5}i##
 
Last edited:
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The modulus is a real number, so it can't be ##\frac 6 5 i##.
 
PeroK said:
The modulus is a real number, so it can't be ##\frac 6 5 i##.
True, its supposed to be ##\dfrac {6}{5}##
 

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