Find zeros f(x)=(x/100)-sin(x)

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Discussion Overview

The discussion revolves around finding the zeros of the function \( f(x) = \frac{x}{100} - \sin(x) \). Participants explore the mathematical properties of the function, including its intersections with the sine curve, and the implications of these intersections for determining the number of roots within a specified range.

Discussion Character

  • Mathematical reasoning
  • Exploratory
  • Homework-related

Main Points Raised

  • One participant states the equation \( f(x) = 0 \) leads to \( \sin x = \frac{x}{100} \) and discusses the bounds for \( x \) based on the properties of the sine function.
  • Another participant calculates that there are approximately 32 intersection points from 0 to 100 and similarly from -100 to 0, concluding a total of 63 roots, accounting for the double counting at \( x = 0 \).
  • A different participant suggests that while exact solutions may not be obtainable, approximate solutions can be found using a graphing calculator in the appropriate mode.
  • A later reply expresses appreciation for the explanation regarding the setup of periods in the context of the sine function.

Areas of Agreement / Disagreement

Participants generally agree on the method of finding the zeros and the approximate number of roots, but there is no consensus on the exactness of the solutions or the method of calculation.

Contextual Notes

The discussion includes assumptions about the behavior of the sine function and the linear function, as well as the limitations of numerical methods for finding roots.

karush
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$f(x)=(x/100)-sin(x)$
Find the zeros

Thot my TI was going to melt trying to solve this
 
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$f(x)=0 \Rightarrow \sin x =\frac{x}{100}$

Since $|\sin x| \leq 1$ we conclude that $\left | \frac{x}{100} \right | \leq 1 \Rightarrow |x| \leq 100 \Rightarrow -100 \leq x \leq 100$.

At each period of $\sin x$, the line $y=\frac{x}{100}$ will intersect the curve $y=\sin x$ twice.
Wolfram|Alpha Widget: Math Help Boards: Graph Plotter

From $0$ to $100$ there are $\frac{100}{2\pi}\approx 16$ periods. So, from $0$ to $100$ there are $2 \cdot 16=32$ intersection points.

Similarily, from $-100$to $0$ there are $32$ intersection points.

So, in total there are $32+32-1=63$ (we have count the point $0$ twice) intersection points.

So, the function $f(x)$ has $63$ roots.
 
karush said:
$f(x)=(x/100)-sin(x)$
Find the zeros

Thot my TI was going to melt trying to solve this

You aren't going to be able to get exact solutions, but your TI should still be able to give you approximate ones. Make sure you're in either Auto or Approx mode, and then type in

solve( x/100 = sin(x) , x)
 
That was amazing, i didn't know how to set up the periods
MHB always out does the textbooks
Much thanks
 

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