Find zeros f(x)=(x/100)-sin(x)

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SUMMARY

The function \( f(x) = \frac{x}{100} - \sin(x) \) has a total of 63 roots within the interval \([-100, 100]\). This conclusion is drawn from the analysis of the intersections between the line \( y = \frac{x}{100} \) and the curve \( y = \sin(x) \), which occurs twice per period of \( \sin(x) \). With approximately 16 periods from 0 to 100, there are 32 intersections in that range, and an additional 32 from -100 to 0, minus one for the double-counted root at \( x = 0 \). The approximate solutions can be found using a TI calculator in Auto or Approx mode with the command solve(x/100 = sin(x), x).

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karush
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$f(x)=(x/100)-sin(x)$
Find the zeros

Thot my TI was going to melt trying to solve this
 
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$f(x)=0 \Rightarrow \sin x =\frac{x}{100}$

Since $|\sin x| \leq 1$ we conclude that $\left | \frac{x}{100} \right | \leq 1 \Rightarrow |x| \leq 100 \Rightarrow -100 \leq x \leq 100$.

At each period of $\sin x$, the line $y=\frac{x}{100}$ will intersect the curve $y=\sin x$ twice.
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From $0$ to $100$ there are $\frac{100}{2\pi}\approx 16$ periods. So, from $0$ to $100$ there are $2 \cdot 16=32$ intersection points.

Similarily, from $-100$to $0$ there are $32$ intersection points.

So, in total there are $32+32-1=63$ (we have count the point $0$ twice) intersection points.

So, the function $f(x)$ has $63$ roots.
 
karush said:
$f(x)=(x/100)-sin(x)$
Find the zeros

Thot my TI was going to melt trying to solve this

You aren't going to be able to get exact solutions, but your TI should still be able to give you approximate ones. Make sure you're in either Auto or Approx mode, and then type in

solve( x/100 = sin(x) , x)
 
That was amazing, i didn't know how to set up the periods
MHB always out does the textbooks
Much thanks
 

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