Finding a basis for a set of polynomials and functions

[trap101]

Find a basis for and the dimension of the subspaces defined for each of the following sets of conditions:

{p \in P₃(R) | p(2) = p(-1) = 0 }

{ f\inSpan{e^x, e^2x, e^3x} | f(0) = f'(0) = 0}


Attempt: Having trouble getting started...

So I think my issue is interpreting what those sets are and setting it up. So I think the sets are: i) the set of all polynomials s.t P(2) = p(-1) = 0 and ii) the set of exp functions where at 0 equal 0.

So how do I put these each into a matrix form to find the basis and dimension?

 

[jbunniii]

Find a basis for and the dimension of the subspaces defined for each of the following sets of conditions:

{p \in P₃(R) | p(2) = p(-1) = 0 }

{ f\inSpan{e^x, e^2x, e^3x} | f(0) = f'(0) = 0}


Attempt: Having trouble getting started...

So I think my issue is interpreting what those sets are and setting it up. So I think the sets are: i) the set of all polynomials s.t P(2) = p(-1) = 0

I doubt this. It is probably the set of all polynomials with degree <= 3, such that p(2) = p(-1) = 0.

and ii) the set of exp functions where at 0 equal 0.

Not just any exp functions. They have to be in \text{span}(e^x, e^{2x}, e^{3x}).

I suggest that you start by finding the dimension of these two spaces: P_3(\mathbb{R}) and \text{span}(e^x, e^{2x}, e^{3x}). Also, what is the form of a general element for each of these two spaces?

 

[HallsofIvy]

Personally, I wouldn't use a matrix, I would use the basic definition. First, I am going to assume that P₃ is the vector space of polynomials of degree 3 or less, which has dimension 4 (some texts use that to mean the space of polynomials 2 or less which has dimension 3- the same ideas will apply but it is simpler). Any such polynomial canbe written p(x)= ax^3+ bx^2+ cx+ d. The condition that p(2)= 0 means that we must have p(2)= 8a+ 4b+ 2c+ d= 0 or d= -(8a+ 4b+ 2c). The condition that p(-1)= 0 means that -a+ b- 2c+ d= 0[/tex] or d= -(a- b+ 2c). Then d= -(8a+ 4b+ 2c)= -(a- b+ 2c) so that 8a+ 4b+ 2c= a- b+ 2c which reduces to 7a= -5b. Sp we can replace a by -5b/7 which means d= -(-(5/7)b- b+ 2c)= -(12/7)b- 2c. Using those, ax^3+ bx^2+ cx+ d= -(5/7)bx^3+ bx^2+ cx- (12/7)b- 2c= (-(5/7)x^3+ x^2- 12/7)b+ c(x- 2)<br /> <br /> Now, do you see what a basis is and what the dimension is?<br /> (You could have made a quick &quot;guess&quot; at what the dimension is by the fact that the basic space has dimension 4 and there are 2 conditions put on it.)<br /> <br /> For the second one, any f in the span of e^x, e^2x, and e^3x, can be written as f(x)= ae^x+ be^2x+ ce^3x, and f&#039;(x)= ae^x+ 2be^x+ 3ce^x.<br /> <br /> The condition that f(0)= 0 gives a+ b+ c= 0 and f&#039;(0)= 0 gives a+ 2b+ 3c= 0. We can subtract the first equations from the second to get b+ 2c= 0 or b= -2c. Putting that into the first equation a- 2c+ c= a- c= 0 so a= c. That is, we can write ae^x+ be^x+ ce^x= ce^{x[/sup- 2ce^2x+ ce^3x= c(e^x- 2e^2x+ e^3x. Now, what is the dimension and what is a basis?<br /> (Here, the basic space has dimension three and there are two conditions.)}

 

[trap101]

I doubt this. It is probably the set of all polynomials with degree <= 3, such that p(2) = p(-1) = 0.

Not just any exp functions. They have to be in \text{span}(e^x, e^{2x}, e^{3x}).

I suggest that you start by finding the dimension of these two spaces: P_3(\mathbb{R}) and \text{span}(e^x, e^{2x}, e^{3x}). Also, what is the form of a general element for each of these two spaces?

That's what I intend on doing, but my issue is setting it up in order ot find those dimensions. So here's how I'm trying to piece it together:

I know the general form for P₃(R) is: ax³+bx²+cx+d, now the condition is that p(2) = P(-1) = 0. So I have to some how write out a set of vectors that satisfy that form.

As for ii) a function would be f(x) = e^x-2e^2x+e^3x, but I'm utterly clueless as to how this is line independent and how I could even find this vector if I set up a matrix