Finding a limit without l'hopial

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SUMMARY

The limit as x approaches 2 for the expression ((sqrt(6-x)-2) / (sqrt(3-x) - 1) can be evaluated without using L'Hôpital's Rule. By multiplying both the numerator and denominator by the conjugate of the denominator, (sqrt(3-x) + 1), the expression simplifies. This method effectively eliminates the indeterminate form and allows for direct evaluation of the limit.

PREREQUISITES
  • Understanding of limits in calculus
  • Knowledge of algebraic manipulation, specifically rationalizing denominators
  • Familiarity with square root functions
  • Basic problem-solving skills in calculus without L'Hôpital's Rule
NEXT STEPS
  • Practice evaluating limits using algebraic techniques
  • Explore the concept of rationalizing denominators in more complex expressions
  • Study alternative methods for finding limits without L'Hôpital's Rule
  • Review the properties of square root functions and their behavior near critical points
USEFUL FOR

Students in high school mathematics, particularly those in calculus courses, educators teaching limit concepts, and anyone seeking to strengthen their problem-solving skills in calculus without relying on advanced techniques like L'Hôpital's Rule.

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Homework Statement


lim x→2 ((sqrt(6-x)-2) / (sqrt(3-x) - 1)


Homework Equations


none


The Attempt at a Solution


My daughter's grade 12 mathematics class is not yet using l'hopital, yet this question has been posed as a practice question. I can solve it readily with l'hopital, however without it I'm stumped. When I attempt by multiplying numerator and denominator by (sqrt(3-x) +1 ) predictably I get 0 for my troubles.
 
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