Finding a point where a line in parametric form meets a plane

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SUMMARY

The discussion focuses on finding the intersection point between a parametric line defined by the equations x = y - 1 = 2z and a plane represented by the equation 4x - y + 3z = 8. The normal vector of the line is identified as <1, 1, -1/2>. Participants emphasize solving the simultaneous equations to determine the point of intersection, which is essential for understanding the relationship between lines and planes in three-dimensional space.

PREREQUISITES
  • Understanding of parametric equations
  • Knowledge of plane equations in three-dimensional geometry
  • Ability to solve simultaneous equations
  • Familiarity with vector notation and operations
NEXT STEPS
  • Study methods for solving parametric equations
  • Learn about the geometric interpretation of lines and planes in 3D space
  • Explore techniques for finding intersections of lines and planes
  • Review vector algebra and its applications in geometry
USEFUL FOR

Students in mathematics or engineering fields, educators teaching geometry, and anyone interested in mastering the concepts of lines and planes in three-dimensional space.

jcfor3ver
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Homework Statement



Here is the problem:

x=y-1=2z

and the equation of the plane is 4x-y+3z=8





Homework Equations





The Attempt at a Solution



Ya so i got the normal line to be <1,1,-1/2> but i do not know where to go from here? help please?
 
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hi jcfor3ver! :wink:

you want the point that lies on both lines?

then just solve the pair of simultaneous equations! :smile:
 

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