Finding a Transfer Function using Laplace

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SUMMARY

The discussion focuses on deriving the transfer function H(s) for a circuit using Laplace transforms. The user presents equations based on Kirchhoff's Voltage Law (KVL) for both loops in the circuit, leading to the expression H(s) = 5000/(3(s+5000)). However, the user expresses doubt regarding the accuracy of their calculations, particularly the impedance of the capacitor, which they believe should be 1/(50E-6) instead of 2E6. This indicates a potential error in the impedance calculation that affects the transfer function.

PREREQUISITES
  • Understanding of Laplace transforms and their application in circuit analysis
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Knowledge of transfer functions in control systems
  • Basic concepts of capacitor impedance in the s-domain
NEXT STEPS
  • Verify capacitor impedance calculations in the s-domain
  • Learn how to derive transfer functions using Laplace transforms
  • Study Bode plot generation for transfer functions
  • Explore common mistakes in circuit analysis using KVL
USEFUL FOR

Electrical engineers, control system designers, and students studying circuit analysis who are interested in deriving transfer functions and analyzing circuit behavior using Laplace transforms.

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I'm trying to find the Transfer function of the circuit below so that I can draw the Bode plot for it. I chose to use Laplace because I think it made it a little simpler.
7hRIx.png


My equations so far:

KVL of Left Loop: EQUATION1
Vs=I1(900+1800)-900I2

KVL of Right Loop: EQUATION2
0=((2E6)/s+400+900)I2-900I1

EQUATION3
Vo=I2*(2E6)/s

Rearranging EQUATION2 gives:
I1=(1/900)((2E6)/s +1300)I2
Substitute this back into EQUATION1 to get Vs in terms of I2 and s.

When I do:
H(s)= Vo/Vs
I get:
H(s)= 5000/(3(s+5000))

Which I'm pretty sure is wrong.
 
Last edited:
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I think you'll want to check the math for your capacitor impedance; 1/(50E-6) is not 2E6.
 

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