Finding Acceleration in Two-Dimensional Kinematics

  • Thread starter Thread starter indietro
  • Start date Start date
  • Tags Tags
    Kinematics
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
9 replies · 2K views
indietro
Messages
46
Reaction score
0

Homework Statement


a flying saucer manueverign with a constant acceleration is observed with the positions and velocities shown below. what is the saucer's acceleration?

Homework Equations


a = [tex]\Delta[/tex]v / t

The Attempt at a Solution


so a time is not given.. is there another way to find acceleration?
** actually if someone knows a site that gives a clear and concise tutorial on two-dimensional kinematics that would be great :). I know there is one attached to this site.. but i do better with actual examples and more visual.
 

Attachments

  • 7.jpg
    7.jpg
    3.1 KB · Views: 429
Physics news on Phys.org
indietro said:
a flying saucer manueverign with a constant acceleration is observed with the positions and velocities shown below. what is the saucer's acceleration?

so a time is not given.. is there another way to find acceleration?

Hi indietro! :smile:

(I can't see the picture yet, but …)

The standard trick for finding dv/dt from v and s without involving t is to use the chain rule …

dv/dt = dv/dx dx/dt = v dv/dx :wink:
 
oo ok for the picture it is a x-y graph that shows a point at (0.0) with a vertical vector (200[tex]\hat{j}[/tex] m/s) and a second point at (2000, 1000) with a south-east vector (200[tex]\hat{i}[/tex] - 100[tex]\hat{j}[/tex] m/s)

for the chain rule: is the v the final velocity?
 
so i have a question: for an x-y graph showing the trajectory, what does [tex]\vec{r}[/tex] (starts at origin and goes to a point on the trajectory) tell me? the velocity at that point? or does it only tell me the direction of velocity at that point?
 
sorry but I am really confused as how to relate an xy-graph, a vx graph, a vy graph and acceleration. Like what does each tell me, how can i find position after a certain time, how can i find acceleration?
 
Hi indietro! :smile:

(just got up :zzz: …)
indietro said:
so i have a question: for an x-y graph showing the trajectory, what does [tex]\vec{r}[/tex] (starts at origin and goes to a point on the trajectory) tell me? the velocity at that point? or does it only tell me the direction of velocity at that point?

r only tells you the position, and the direction of the tangent of the trajectory tells you the direction of the velocity.
indietro said:
sorry but I am really confused as how to relate an xy-graph, a vx graph, a vy graph and acceleration. Like what does each tell me, how can i find position after a certain time, how can i find acceleration?

Why are you using a graph? Does the question tell you to?

If it doesn't, then forget graphs, and just use equations. :smile:
 
yes the question gives me all the information in the form of an vx graph and vy graph ...:(
 
indietro said:
yes the question gives me all the information in the form of an vx graph and vy graph ...:(

hmm … I still can't see your picture.

I'll have to wait until I can see it.

(I've reported it, so hopefully it'll come up soon :redface:)
 
oooh, I see it now! :-p

ok, that isn't a graph (a graph would be a continuous curve) …

it's just a diagram, defining the two velocities in a picture instead of in words.

So you don't have to use a "graph method" …

just write the velocities as 200j and 200i - 100j, and carry on from there. :smile: