Finding acceleration of box- given mass of box and magnitude of frict

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To find the acceleration of a 10kg box sliding across the floor with a frictional force of 40 N, the net force acting on the box is equal to the frictional force. Using the formula Fnet = ma, the acceleration can be calculated as a = Fnet/m. Substituting the values gives a = 40 N / 10 kg, resulting in an acceleration of 4 m/s². It's noted that while acceleration is a vector quantity, in this case, the direction is implied by the context of the motion. The calculation is correct, confirming the acceleration of the box.
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Finding acceleration of box-- given mass of box and magnitude of frict

Doing homework and stuck on this question. A student pushes a 10kg box and let's it slide across the floor. The magnitude of the frictional force acting on the box is 40 N. What is the acceleration of the box?


Relative equations:
Fnet=ma
a=fnet/m

Attempt:

Fnet=ma
a=fnet/m
a=40N/10kg
a=4 m/s2

I know this is probably wrong, I am just so confused...
 
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acceleration is a vector ... you need to include the direction somehow.
Apart from that you are quite correct - there is only one force on the box and F=ma.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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