Finding Acceleration of Gravity for Springs Without a Given K

In summary, the conversation discusses the process of finding the acceleration of gravity for a spring without a given spring constant. The individual is struggling to calculate the spring constant and acceleration of gravity using the given values for period, mass, and displacement. They attempted to use the equation for the period of a mass-spring system, but were unsuccessful. The question is raised about the meaning of "displacement" in this context.
  • #1
Luna413
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Finding Acceleration of Gravity for Springs Without a Given "K"

Homework Statement



What I need is to gather data for the period, displacement, and mass of a certain object put on a spring. Later, I was asked to find the gravity--however I wasn't given a spring constant and I'm left on my own. I haven't been able to successfully calculate a spring constant and acceleration of gravity (I've tried to do this since Monday). For example:

I have:
Period: .96s
Mass: 100g
Displacement: 45cm


Homework Equations



F=-kx

T=2[itex]\pi[/itex][itex]\sqrt{m/k}[/itex]

The Attempt at a Solution



I thought I could solve for K using the Period of a Mass-Spring System equation (T=...), however, it seems I can't... so I'm a bit lost.
 
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  • #2


What is "displacement"?

Why can't you find k given the period and the mass?
 

FAQ: Finding Acceleration of Gravity for Springs Without a Given K

What is the formula for finding acceleration of gravity for springs without a given K?

The formula for finding acceleration of gravity for springs without a given K is a = (mg)/x, where a is the acceleration of gravity, m is the mass of the object attached to the spring, and x is the displacement from the equilibrium position.

What is the significance of finding the acceleration of gravity for springs?

Finding the acceleration of gravity for springs is significant because it helps us understand the behavior of objects attached to springs and how they respond to the force of gravity. This information is important in fields such as engineering and physics.

Can the acceleration of gravity for springs vary?

Yes, the acceleration of gravity for springs can vary depending on factors such as the mass of the object attached to the spring, the stiffness of the spring, and the force of gravity. It is important to take these factors into account when calculating the acceleration of gravity for springs.

What is the unit of measurement for acceleration of gravity for springs?

The unit of measurement for acceleration of gravity for springs is meters per second squared (m/s²). This is a unit of acceleration and represents the change in velocity (in meters per second) over time (in seconds).

How can we determine the acceleration of gravity for springs experimentally?

To determine the acceleration of gravity for springs experimentally, we can use a simple pendulum experiment. By measuring the period of the pendulum and the length of the string, we can calculate the acceleration of gravity using the formula a = (4π²L)/T², where a is the acceleration of gravity, L is the length of the pendulum, and T is the period of the pendulum.

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