- #1
riri
- 28
- 0
Hello!
I've encountered a problem of find all points (x,y) on $f(x)=\frac{x-\sqrt{\pi}}{x+1}$ where there are tangent lines perpendicular to $y=-(1+\sqrt{\pi}x+7\pi e^{e^{{\pi}^{110}}})$
So I first found derivative and ended up with $f'(x)=\frac{1(x+1)-(x-\sqrt{\pi})(1)}{x^2+2x+1}$
and then simplified and got to $\frac{1+\sqrt{\pi}}{x^2+2x+1}$
and then I think i equal this to $\frac{1}{1+\sqrt{\pi}}$ because it's perpendicular... and then I don't know what to do. Do they cross out to be $\frac{1}{x^2+2x+1}$?Thank you!
I've encountered a problem of find all points (x,y) on $f(x)=\frac{x-\sqrt{\pi}}{x+1}$ where there are tangent lines perpendicular to $y=-(1+\sqrt{\pi}x+7\pi e^{e^{{\pi}^{110}}})$
So I first found derivative and ended up with $f'(x)=\frac{1(x+1)-(x-\sqrt{\pi})(1)}{x^2+2x+1}$
and then simplified and got to $\frac{1+\sqrt{\pi}}{x^2+2x+1}$
and then I think i equal this to $\frac{1}{1+\sqrt{\pi}}$ because it's perpendicular... and then I don't know what to do. Do they cross out to be $\frac{1}{x^2+2x+1}$?Thank you!
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