Finding an ellipse from a plane slicing a cone

Click For Summary
SUMMARY

The discussion focuses on deriving the parameters \(a\) and \(b\) of an ellipse formed by slicing a right circular cone with a plane. The ellipse is represented by the equation \(\frac{x^2}{a} + \frac{y^2}{b} = 1\), where the minor semi-axis \(\sqrt{b}\) is determined by the cone's radius at height \(h\). The major semi-axis \(\sqrt{a}\) can be calculated using the relationship \(a = \frac{b}{\tan(\theta/2)}\), where \(\theta\) is the cone's opening angle. The use of Dandelin spheres is also discussed as a method to visualize the relationship between the cone and the ellipse.

PREREQUISITES
  • Understanding of conic sections, specifically ellipses
  • Knowledge of geometry involving right circular cones
  • Familiarity with trigonometric functions and their applications
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the properties of Dandelin spheres and their application in conic sections
  • Learn how to derive the equations of ellipses from geometric principles
  • Explore the relationship between angles in triangles formed by conic sections
  • Investigate the derivation of ellipse parameters using calculus and analytic geometry
USEFUL FOR

Students studying geometry, mathematics educators, and anyone interested in the mathematical properties of conic sections and their applications in real-world scenarios.

anomiet
Messages
4
Reaction score
0
Hello,

So I'm doing some independent study and I'm at a loss for this problem.

Homework Statement



Let's say we have an ellipse of the form (x2)/a + (y2)/b = 1 which we obtain by slicing a plane through a right circular cone with an opening angle of \theta (a fixed constant). We know the angle the plane makes with the xy-plane to be \phi. We also know the cut crosses the center line of the cone at height h. In terms of h and \phi, what is a and b?

Homework Equations



I found this page that seemed to be pointing me in the right direction, but I can't make much sense of it:

http://www.physicsinsights.org/conic_sections_1.html

Also, the equation of the ellipse they are using is related to the foci of the ellipse which I don't know how to relate to the equation of an ellipse I'm looking for.

The Attempt at a Solution



I'm honestly not sure where to start or if this is possible. It seems to me like it should be, so any help would be greatly appreciated.

Thank you,
-anomie
 
Physics news on Phys.org
Last edited by a moderator:
Thanks for the quick reply!

I'm imagining the process to get the major and minor radius of the ellipse would go something like this: Get the points of each sphere that touch the plane from above and below. This will be the foci of your ellipse, which in turn you can formulate the equation of the ellipse.

So how would I go about getting the Dandelin spheres with just the information in my above post? Essentially, how do I get the Dandelin spheres tangent to both a given plane and a given cone?

Thank you,
-anomie
 
hello anomie! :smile:

(just got up :zzz: …)
anomiet said:
So how would I go about getting the Dandelin spheres with just the information in my above post? Essentially, how do I get the Dandelin spheres tangent to both a given plane and a given cone?

you wouldn't bother … there obviously are such spheres (they're the largest possible inscribed spheres), and their mere existence proves that it is an ellipse (or parabola or hyperbola, depending on the slope)

once you know it is an ellipse, you know that the minor semi-axis, √b, is simply the radius of the cone at height h, and you can find the major semi-axis, √a, from the obvious triangle :wink:

(and you can find the foci using the usual formula)

btw, we usually write an ellipse with a and b squared … x2/a2 + y2/b2 = 1 … to make calculations easier!)
 
Ok, sweet, things are starting to make more sense. Thanks for the great help!:smile:

I was easily able to get the minor axis. As for the major axis, I'm not getting the right results. I tried using the right triangle that is formed on the ellipse with the sides being the semi-minor and semi-major axes. I determined that the angle formed with the hypotenuse and semi-major axis is always going to be half of opening angle (\theta/2). Thus, knowing the semi-minor axis, I can solve for a using a=b/(tan(\theta/2)). An image below to show what I mean:

rQviq.png


The thing that I'm not sure on is that the angle is indeed always half of the opening angle (which I'm really starting to doubt now). The other triangle I tried to use was the one formed by the center line of the cone, the semi-major axis, and the line formed by the edge of the cone. Yet, I still get vastly disproportional results.

Thank you,
-anomie
 
hi anomie! :smile:
anomiet said:
I determined that the angle formed with the hypotenuse and semi-major axis is always going to be half of opening angle … The thing that I'm not sure on is that the angle is indeed always half of the opening angle (which I'm really starting to doubt now).

no it isn't! :redface:
The other triangle I tried to use was the one formed by the center line of the cone, the semi-major axis, and the line formed by the edge of the cone.

that should do it …

what result did you get? :smile:
 
Hello!

So it looks like I was doing it right overall but just had some arithmetic errors I glanced over when it came to the finding the major axis. The math makes sense to me know thanks to you!:smile:

Thanks a lot for the help!

-anomie
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
4K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K