Finding an expression for torque

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Homework Statement



http://www.physics.ox.ac.uk/users/yassin/mechanics/problems/probs6_2011.pdf

Q 2b.

Homework Equations





The Attempt at a Solution



T is torque and J is angular momentum.
T=dJ/dt=I dω/dt

I tried solving dω/dt=ωk to get dω/dt=ce^kt, but this may not help.
 
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Lucy Yeats said:

Homework Statement



http://www.physics.ox.ac.uk/users/yassin/mechanics/problems/probs6_2011.pdf

Q 2b.

Homework Equations


The Attempt at a Solution



T is torque and J is angular momentum.
T=dJ/dt=I dω/dt

I tried solving dω/dt=ωk to get dω/dt=ce^kt, but this may not help.

They represented torque as N.

You're given N = kω ---equation 1

You also know that N = -I[itex]\frac{dω}{dt}[/itex] ---equation 2
(the negative sign is to keep N positive since they're concerned with the numerical value for torque).

You can equate equations 1 and 2 to get kω = -I[itex]\frac{dω}{dt}[/itex]

and solve the differential equation. Remember to apply the given bounds using definite integrals on both sides after separating the variables ω and t.

After that, express k in terms of the other variables, and put this back into equation 1 to get N.
 
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Great, I've got the right answer now.

Thank you very much! :-)
 
Lucy Yeats said:
Great, I've got the right answer now.

Thank you very much! :-)

You're welcome. :smile: