Finding an Integral from an Unknown Function

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Homework Statement


If xsin[tex]\pi[/tex]x = [tex]\int[/tex]f(t) dt, where is a continuous function, find f(4).
b=x2, a=0

Homework Equations





The Attempt at a Solution


I assumed that the problem dealt with the Fundamental Theroem of Calculus so I began by saying that g(x)=xsin[tex]\pi[/tex]x but that is as far as it makes sense to me. Could anyone confirm to me that I am following the correct path?
 
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Yes, if
[tex]x sin(\pi x)= \int_0^{x^2} f(t)dt[/quote]<br /> you can apply the Fundamental theorem but if you do that, because the upper limit is "x<sup>2</sup>" rather than "x", you need to use the chain rule also:<br /> [tex]F(x)= \int_0^x^2 f(t)dt= \int_0^u f(t)dt[/tex]<br /> where u= x<sup>2</sup>. The derivative of the right hand side is F'(u)(du/dx)= f(u)(2x)= f(x<sup>2</sup>)(2x). That is equal to the derivative of the left hand side. What is the derivative of [itex]x sin(\pi x)[/itex]?<br /> [tex]f([/tex][/tex]