- #1
ISU20CpreE
- 69
- 0
Hi there i am trying to make this equation look exact.
[tex](Cos(2y)-Sin (x)) dx-2 Tan (x) Sin (2y) dy = 0 [/tex]
What I've done so far is take the partial with respect to x and y.
So, my
[tex]M_{y}[/tex] is equal to [tex]-2 Sin (2y)-0[/tex] and,
my [tex]N_{x}[/tex] is equal to [tex]-2(Sec^{2}(x)) Sin (2y)[/tex]
Which makes it not exact. So, then I tried using
[tex]\frac{M_{y}-N_{x}}{-N}[/tex] and,
here is where I have tried so many times to find out a way to find an Integration Factor (I.F.)
Any suggestions will help, thanks for your time.
[tex](Cos(2y)-Sin (x)) dx-2 Tan (x) Sin (2y) dy = 0 [/tex]
What I've done so far is take the partial with respect to x and y.
So, my
[tex]M_{y}[/tex] is equal to [tex]-2 Sin (2y)-0[/tex] and,
my [tex]N_{x}[/tex] is equal to [tex]-2(Sec^{2}(x)) Sin (2y)[/tex]
Which makes it not exact. So, then I tried using
[tex]\frac{M_{y}-N_{x}}{-N}[/tex] and,
here is where I have tried so many times to find out a way to find an Integration Factor (I.F.)
Any suggestions will help, thanks for your time.