Finding angle and Forces in a system

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SUMMARY

The discussion focuses on analyzing a Y-shaped system with a 12kg weight hanging from the bottom, resulting in a force of 117.72N due to gravity. The equations established for the system include the sum of forces in the x-direction (Sum Fx: F cos 25 - F cos Q = 0) and the sum of forces in the y-direction (Sum Fy: F sin 25 + F sin Q = -117.72). It is concluded that since the two forces are equal, the angles can indeed be considered equal, confirming the friend's suggestion that the other angle is also 25 degrees.

PREREQUISITES
  • Understanding of static equilibrium in physics
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with force analysis in two dimensions
  • Basic knowledge of Newton's laws of motion
NEXT STEPS
  • Study static equilibrium problems in physics
  • Learn about vector decomposition in force analysis
  • Explore trigonometric identities and their applications in physics
  • Investigate the principles of tension in Y-shaped systems
USEFUL FOR

This discussion is beneficial for physics students, engineers, and anyone involved in mechanics or structural analysis, particularly those working with static systems and force equilibrium.

imagiro1
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1. The system is set up in a y shape. A weight of 12kg is hanging from the bottom. One of the angles formed with respect to the x-axis is 25. We are also told the 2 forces are equal.


2. Sum of forces in the x directions = 0. Sum of forces in the y direction = 0. 12kg*9.81 = 117.72N.


3. Since the 2 forces are equal. I have made the following equations.
Sum Fx: F cos 25 - F cos Q = 0
Sum Fy: F sin 25 + F sin Q = -117.72

I am looking for Fa, Fb, and the other angle.

My friend has suggested to make the angles equal to each other since the forces are equal, but that doesn't seem like it would be correct.

I am just looking for a way to get this started.
 
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imagiro1 said:
1. The system is set up in a y shape. A weight of 12kg is hanging from the bottom. One of the angles formed with respect to the x-axis is 25. We are also told the 2 forces are equal.


2. Sum of forces in the x directions = 0. Sum of forces in the y direction = 0. 12kg*9.81 = 117.72N.


3. Since the 2 forces are equal. I have made the following equations.
Sum Fx: F cos 25 - F cos Q = 0
Sum Fy: F sin 25 + F sin Q = -117.72

I am looking for Fa, Fb, and the other angle.

My friend has suggested to make the angles equal to each other since the forces are equal, but that doesn't seem like it would be correct.

I am just looking for a way to get this started.

From your sum of Fx equation, since you know that F≠0, why don't you divide by F?
 
Cause that's too easy. ;) Yup, then the other angle is 25. Guess my friend was right. Thanks.
 

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