1. The problem statement, all variables and given/known data Three particles with masses m1=2.5kg, m2=1.2kg and unknown mass m3 are placed at the corners of an equilateral triangle of side 30.0cm. If the resultant force in x-direction acting on m1 is zero, find the net force acting on m1. 2. Relevant equations F=(Gm1m2)/R^2 Fx=Fcosθ Fy=Fsinθ F=sqrt/(Fx)^2 +(Fy)^2 3. The attempt at a solution Since Fx on m1=0 Fm1 cos 60 = 0 Fm1 = 0 The Fy on m1 = 0 Fy = Fm1 sin 60 Fy = 0 sin 60 Fy = 0 So does it mean the net force acting on m1 is F=sqrt/(0)^2 +(0)^2 F=0N ?