Finding Angle Between Lines Passing Through Points (-2,-1) and (4,1)

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Homework Help Overview

The discussion revolves around finding the angle between two lines, specifically one defined by the equation 3x-2y=4 and another line that connects the points (-2,-1) and (4,1). Additionally, there is a related question about finding the equation of a line passing through a specific point with a given inclination.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the need for a point and the gradient to find the equation of a line. There is a suggestion to use the tangent of the angle to determine the gradient. Some participants also question the use of "Celsius" instead of "degrees" in the context of angle measurement.

Discussion Status

There are attempts to clarify the relationship between the angle and the gradient, with some participants providing calculations for the gradient based on the angle. However, discrepancies in calculations have been noted, indicating ongoing exploration of the problem without a clear consensus on the correct approach.

Contextual Notes

One participant expresses a lack of understanding due to being away from school, indicating a possible gap in foundational knowledge that may affect their ability to engage with the problem fully.

cherrypie
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Homework Statement



Find the equation of a straight line which passes through the point (2,3) and is inclined at 30 Celsius to the positive direction of the x-axis.

The Attempt at a Solution


i have no idea how to to this question as i was away for a week of school >< and my teacher gave my catch up worksheets. I am falling behind class. so need help

Homework Statement


find the angle between the straight line 3x-2y=4 and the line joining the points (-2,-1) and (4,1)

please guide me step by step

thanks
 
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What you need for the first one is a point on the line (which you were given) and the gradient.
This will help you to get the gradient:

Tan(angle the line makes with the +ve x-axis)=gradient of the line.

EDIT: I think you mean 30 degrees and not celsius as that implies a temperature.
 
Last edited:
rock.freak667 said:
What you need for the first one is a point on the line (which you were given) and the gradient.
This will help you to get the gradient:

Tan(angle the line makes with the +ve x-axis)=gradient of the line.

EDIT: I think you mean 30 degrees and not celsius as that implies a temperature.

so y=mx+c
Tan(30degrees) is m =0.56
so y=0.56x+c

find c, sub (2,3)

y=0.56x+1.85 ?
 
(0.56)(2)+ 1.85= 1.12+ 1.85= 2.97, not 3. Did you mean tan(30)= 0.58?
 

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